Shahmir123
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Hydrogen ion concentration in 25cm3 sample of sulfuric acid with 0.025 moles
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annon222
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A bit rusty on this, but I think
0.025*2*6.022e23
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Shimo
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Well for starters work out the concentration of the sulphuric acid. M = n/V, so 0.025/0.025 = 1M. Sulphuric acid is a diprotic acid, so it has two hydrogen atoms that can dissociate, however you can ignore the second dissociation as it's weak in comparison to the first. Since it's a strong acid the concentration of the acid is the same as the hydrogen ions as it fully dissociates, so [H+] = 1M.
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Pigster
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(Original post by Shimo)
Well for starters work out the concentration of the sulphuric acid. M = n/V, so 0.025/0.025 = 1M. Sulphuric acid is a diprotic acid, so it has two hydrogen atoms that can dissociate, however you can ignore the second dissociation as it's weak in comparison to the first. Since it's a strong acid the concentration of the acid is the same as the hydrogen ions as it fully dissociates, so [H+] = 1M.
The second dissociation may be weak, but is near as damn it considered strong, so the [H+] is very nearly 2x[H2SO4]
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