olivia.scoble
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GeorgePotter
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(Original post by olivia.scoble)
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ACD = 80.5
to work out area of ABC you need to do 1/2 base x h, you know the base is 19 'i think i can't quite see'
Then use trig to work out the length of A to centre of AC, you have a right angle triangle. You also have to work out AC but looking at the other triangle 1/2 x 14 x h = 80.5, so h = AC = 11.5

you can use sin rule or sohcahtoa, i prefer sine rule. so 11.5/sin90 = x/sin36, so x - 6.76
ans x 1/2 x 19 = 64.2

aplogies if i read the figures wrong
Last edited by GeorgePotter; 1 year ago
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olivia.scoble
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Thank you so much
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GeorgePotter
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(Original post by olivia.scoble)
Thank you so much
No worries, if you have any more you want me to go through or in more detail, my snapchat is george1potter, i was doing a level maths but it got cancelled so im just helping out year 10 and year 12s atm aha
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olivia.scoble
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Thank you so much I’ll add you now
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sumzi_ia
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(Original post by GeorgePotter)
No worries, if you have any more you want me to go through or in more detail, my snapchat is george1potter, i was doing a level maths but it got cancelled so im just helping out year 10 and year 12s atm aha
hi i have a maths question, can you help?
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davros
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(Original post by sumzi_ia)
hi i have a maths question, can you help?
This thread is a year old and that poster hasn't logged on since August 2020!

If you have a question I would suggest starting a new thread of your own and then anyone available can try to help
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