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Meganbw23
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#1
https://share.icloud.com/photos/0mw-...wwp0-xLU3SUphw
Can anyone help me with my a level chemistry task that I’ve been set. It’s about spectroscopy and identifying the compounds. You’ll need something to identify the values on the graph.
Can anyone help me with my a level chemistry task that I’ve been set. It’s about spectroscopy and identifying the compounds. You’ll need something to identify the values on the graph.
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Pigster
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#2
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#2
(Original post by Meganbw23)
https://share.icloud.com/photos/0mw-...wwp0-xLU3SUphw
Can anyone help me with my a level chemistry task that I’ve been set. It’s about spectroscopy and identifying the compounds. You’ll need something to identify the values on the graph.
https://share.icloud.com/photos/0mw-...wwp0-xLU3SUphw
Can anyone help me with my a level chemistry task that I’ve been set. It’s about spectroscopy and identifying the compounds. You’ll need something to identify the values on the graph.
There is a broad peak at about 3300 and a massive peak at about 1700. They should be a massive clue. If the pH less than 7 wasn't enough of a clue for you.
The mass of Br2 gives you the number of mol. The 1:1 ratio with Br2 tells you there is one C=C and therefore how many mol of compound A there is and using the mass, you can work out its Mr, which together with the empirical formula tells you the molecular formula and by now what it could be.
By the way, what does the 'b' stand for?
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Meganbw23
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#3
(Original post by Pigster)
You must be able to work out the empirical formula.
There is a broad peak at about 3300 and a massive peak at about 1700. They should be a massive clue. If the pH less than 7 wasn't enough of a clue for you.
The mass of Br2 gives you the number of mol. The 1:1 ratio with Br2 tells you there is one C=C and therefore how many mol of compound A there is and using the mass, you can work out its Mr, which together with the empirical formula tells you the molecular formula and by now what it could be.
By the way, what does the 'b' stand for?
You must be able to work out the empirical formula.
There is a broad peak at about 3300 and a massive peak at about 1700. They should be a massive clue. If the pH less than 7 wasn't enough of a clue for you.
The mass of Br2 gives you the number of mol. The 1:1 ratio with Br2 tells you there is one C=C and therefore how many mol of compound A there is and using the mass, you can work out its Mr, which together with the empirical formula tells you the molecular formula and by now what it could be.
By the way, what does the 'b' stand for?
How do I work out the mr from the empirical formula
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Pigster
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#4
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#4
(Original post by Meganbw23)
I don’t know what ‘ b’ you’re on about.
How do I work out the mr from the empirical formula
I don’t know what ‘ b’ you’re on about.
How do I work out the mr from the empirical formula
You can work out the Mr since you know the amount of compound A that you have and the mass of A.
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Meganbw23
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#5
(Original post by Pigster)
The b in your username.
You can work out the Mr since you know the amount of compound A that you have and the mass of A.
The b in your username.
You can work out the Mr since you know the amount of compound A that you have and the mass of A.
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Meganbw23
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#6
I literally cannot think right now and I can’t remember how to work out the mr from empirical formula. I don’t understand how to do it.
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Pigster
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#7
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#7
(Original post by Meganbw23)
I literally cannot think right now and I can’t remember how to work out the mr from empirical formula. I don’t understand how to do it.
I literally cannot think right now and I can’t remember how to work out the mr from empirical formula. I don’t understand how to do it.
You can work out how many mol of Br2 reacts and you're told that it reacts with A in a 1:1 reaction, so now you know how many mol of A you have and you're told the mass that that many mol of A has, so you can use n=m/Mr.
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Meganbw23
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#8
(Original post by Pigster)
You can't work out Mr from emp. form.
You can work out how many mol of Br2 reacts and you're told that it reacts with A in a 1:1 reaction, so now you know how many mol of A you have and you're told the mass that that many mol of A has, so you can use n=m/Mr.
You can't work out Mr from emp. form.
You can work out how many mol of Br2 reacts and you're told that it reacts with A in a 1:1 reaction, so now you know how many mol of A you have and you're told the mass that that many mol of A has, so you can use n=m/Mr.
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Pigster
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#9
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#9
(Original post by Meganbw23)
So the empirical formula is C2H3O Would I divide 2.00 by 43.03 which is the formula of the empirical formula
So the empirical formula is C2H3O Would I divide 2.00 by 43.03 which is the formula of the empirical formula
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Meganbw23
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#10
(Original post by Pigster)
You don't have 43.03 mol of Br2.
You don't have 43.03 mol of Br2.
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Meganbw23
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#11
Do you know what the mr is from the data provided? If you could tell me that would be a great starting point for me so that I could actually answer the question.
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Pigster
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#12
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#12
(Original post by Meganbw23)
Do you know what the mr is from the data provided? If you could tell me that would be a great starting point for me so that I could actually answer the question.
Do you know what the mr is from the data provided? If you could tell me that would be a great starting point for me so that I could actually answer the question.
How many mol of A do they react with?
Given that you have 2.00 g of A, what must its Mr be? (n=m/Mr)
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Meganbw23
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#13
(Original post by Pigster)
How many mol of Br2 are there?
How many mol of A do they react with?
Given that you have 2.00 g of A, what must its Mr be? (n=m/Mr)
How many mol of Br2 are there?
How many mol of A do they react with?
Given that you have 2.00 g of A, what must its Mr be? (n=m/Mr)
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Meganbw23
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#14
(Original post by Meganbw23)
I don’t know how many moles of br2 there are lol
I don’t know how many moles of br2 there are lol
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Pigster
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#15
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#15
(Original post by Meganbw23)
0.02 moles of br2 so it would be the same for confound A?
0.02 moles of br2 so it would be the same for confound A?
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Meganbw23
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#16
(Original post by Pigster)
2.00/159.8 isn't quite 0.02, but the real value would also be the amount of A.
2.00/159.8 isn't quite 0.02, but the real value would also be the amount of A.
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Pigster
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#17
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#17
(Original post by Meganbw23)
I know it’s like 0.023 something what would I do next to get the mr of A
I know it’s like 0.023 something what would I do next to get the mr of A
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Meganbw23
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#18
(Original post by Pigster)
As I have said already, use n=m/Mr
As I have said already, use n=m/Mr
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Pigster
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#19
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#19
(Original post by Meganbw23)
Do I rearrange the equation? What values do I use
Do I rearrange the equation? What values do I use
m = mass
Mr = relative molecular mass
You're going to have to do some of the work. I am not here to just do everything for you.
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Meganbw23
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#20
(Original post by Pigster)
n = amount
m = mass
Mr = relative molecular mass
You're going to have to do some of the work. I am not here to just do everything for you.
n = amount
m = mass
Mr = relative molecular mass
You're going to have to do some of the work. I am not here to just do everything for you.
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