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A level physics - help please
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A sinusoidally-varying voltage that has a frequency of 1750 Hz, is applied across a 0.5 W, 24 Ω resistor.
What is the peak value of the voltage such that the resistor is not overloaded?
What is the peak value of the voltage such that the resistor is not overloaded?
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(Original post by Folayemi.f)
A sinusoidally-varying voltage that has a frequency of 1750 Hz, is applied across a 0.5 W, 24 Ω resistor.
What is the peak value of the voltage such that the resistor is not overloaded?
A sinusoidally-varying voltage that has a frequency of 1750 Hz, is applied across a 0.5 W, 24 Ω resistor.
What is the peak value of the voltage such that the resistor is not overloaded?
for calculating power dissipation with sinusoidal AC you need to use Volts RMS (or Amps RMS)
here is why https://www.bbc.co.uk/bitesize/guide...7ty/revision/4
and then convert V RMS to V peak
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(Original post by Joinedup)
Frequency is irrelevant information for a resistive load - is that the complete question?
for calculating power dissipation with sinusoidal AC you need to use Volts RMS (or Amps RMS)
here is why https://www.bbc.co.uk/bitesize/guide...7ty/revision/4
and then convert V RMS to V peak
Frequency is irrelevant information for a resistive load - is that the complete question?
for calculating power dissipation with sinusoidal AC you need to use Volts RMS (or Amps RMS)
here is why https://www.bbc.co.uk/bitesize/guide...7ty/revision/4
and then convert V RMS to V peak
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(Original post by Folayemi.f)
Yes it’s the complete question, I don’t really understand either, and I have no idea how to start
Yes it’s the complete question, I don’t really understand either, and I have no idea how to start
Then convert RMS to peak as shown in the link - if you need help to remember whether you should be multiplying or dividing by the constant sqrt(2) you can remember that peak is always higher than RMS
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