Emily~3695
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I’m struggling to work out part b to this Isaac physics question, the answer to part a is 236 and I tried to work out the answer to part b by doing 236/100pi because that is the circumference of the roundabout, the answer to this is 0.75 however this is not the right answer so I have no idea how to work it out, any help would be very useful

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Last edited by Emily~3695; 6 months ago
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jamiet0185
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Could you tell me what the question is/post a picture of it then I'll do my best to help 😄
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Emily~3695
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(Original post by jamiet0185)
Could you tell me what the question is/post a picture of it then I'll do my best to help 😄
I attached a picture to the post, can you not see it?
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ayumie
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Hey! The attachment is faulty. Could you send another pic etc?
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Emily~3695
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(Original post by ayumie)
Hey! The attachment is faulty. Could you send another pic etc?
Yh of course, this is the question:
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I hadn’t realised that it was faulty as it looks fine on my original post, thanks for letting me know
Last edited by Emily~3695; 6 months ago
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jojicr7
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The distance it has travelled which you found in part a corresponds to how much of the circumference it has covered in the time.
So if you divide the answer from part a by the circumference, then you’ll get how many rounds it has finished.
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Emily~3695
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(Original post by jojicr7)
The distance it has travelled which you found in part a corresponds to how much of the circumference it has covered in the time.
So if you divide the answer from part a by the circumference, then you’ll get how many rounds it has finished.
That’s what I did but it doesn’t get the correct answer which is why I was confused
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Stonebridge
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(Original post by Emily~3695)
That’s what I did but it doesn’t get the correct answer which is why I was confused
Why have you used 100m in the calculation for the circumference
C= Pi x diameter
The diameter of the roundabout is 50m
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ayumie
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9.a. 236m
b. 236/50pi = 1.5025, so roughly 1.5 times.
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