Maths question

I'm practicing for a maths test i'll be sitting tomorrow but I'm stuck on this question:

Lena has 54 red balls and 36 blue balls. She wishes to distribute the balls to create identical bags. What is the
maximum number of bags that she can create if she wishes to have the same number of red balls and the same
number of blue balls in each bag?

Could you please explain to me how this question is done?

I think the answer to your question should be 36 bags.
Let's see why
To have the maximum number of bags for the finite number of balls,each and every bag must have the least possible number of balls.
The condition is that the number of balls of blue and red should be equal in each bag.
So I thought of putting 1 blue ball and 1 red ball in every bag. This is the least number of balls you can put in each bag.
As there are 54 red balls and 36 blue balls, you can have a maximum of 36 red balls and 36 blue balls which are put into 36 bags. You can't do anything with the remaining 18 balls I suppose.
As a matter of curiosity ,which exam is this.

Answer is 18 bags...

If you see my responce in post number 2, I left the final part of the soilution to you but it seems you already have the answer.

take the ratio 54:36 and reduce this down to its lowest form keeping the numbers as integers, 54/36 = 3/2

54/3 = 18 or 36/2 = 18

Hope this helps.
Wasnt planning on spelling it out, but i think thats what you want.