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Jshek
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#1
https://pmt.physicsandmathstutor.com...n%201%20QP.pdf
https://pmt.physicsandmathstutor.com...n%201%20MS.pdf
can you explain the answer to these question as i dont get it
2a) why do the Br disappear and form a double bond
2b) never learnt resistant
3aii)how is it a isomer can you draw the 2 molecule so i can visualise it.
3bii)how does lowering temp increase yield
and 7bi) onwards is it year 2 content as i dont know how to answer it
https://pmt.physicsandmathstutor.com...n%201%20MS.pdf
can you explain the answer to these question as i dont get it
2a) why do the Br disappear and form a double bond
2b) never learnt resistant
3aii)how is it a isomer can you draw the 2 molecule so i can visualise it.
3bii)how does lowering temp increase yield
and 7bi) onwards is it year 2 content as i dont know how to answer it
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Ensoetre
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#2
Ensoetre
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#3
charco
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#4
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#4
(Original post by Jshek)
https://pmt.physicsandmathstutor.com...n%201%20QP.pdf
https://pmt.physicsandmathstutor.com...n%201%20MS.pdf
can you explain the answer to these question as i dont get it
2a) why do the Br disappear and form a double bond
2b) never learnt resistant
3aii)how is it a isomer can you draw the 2 molecule so i can visualise it.
3bii)how does lowering temp increase yield
and 7bi) onwards is it year 2 content as i dont know how to answer it
https://pmt.physicsandmathstutor.com...n%201%20QP.pdf
https://pmt.physicsandmathstutor.com...n%201%20MS.pdf
can you explain the answer to these question as i dont get it
2a) why do the Br disappear and form a double bond
2b) never learnt resistant
3aii)how is it a isomer can you draw the 2 molecule so i can visualise it.
3bii)how does lowering temp increase yield
and 7bi) onwards is it year 2 content as i dont know how to answer it
2b) "resistant to" means that no reaction happens
3a(ii) The double bond can form between the last two carbon atoms
3b(ii) Unclear from the information given. Maybe the reaction is an equilibrium in the forward exothermic direction.
7b(i) I don't know which board you are studying - you wold have to look at the spec.
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Jshek
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#5
(Original post by charco)
2a) you've read the question incorrectly. The alkene MAKES the bromo compound.
2b) "resistant to" means that no reaction happens
3a(ii) The double bond can form between the last two carbon atoms
3b(ii) Unclear from the information given. Maybe the reaction is an equilibrium in the forward exothermic direction.
7b(i) I don't know which board you are studying - you wold have to look at the spec.
2a) you've read the question incorrectly. The alkene MAKES the bromo compound.
2b) "resistant to" means that no reaction happens
3a(ii) The double bond can form between the last two carbon atoms
3b(ii) Unclear from the information given. Maybe the reaction is an equilibrium in the forward exothermic direction.
7b(i) I don't know which board you are studying - you wold have to look at the spec.
2a is understand the double bond but why do br dissapear
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charco
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#6
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#6
(Original post by Jshek)
3aii why does the 4th carbon have Ch3 whereas the last carbon on the original molecule have ch2.
2a is understand the double bond but why do br dissapear
3aii why does the 4th carbon have Ch3 whereas the last carbon on the original molecule have ch2.
2a is understand the double bond but why do br dissapear
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Jshek
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#7
(Original post by Jshek)
3aii why does the 4th carbon have Ch3 whereas the last carbon on the original molecule have ch2.
2a is understand the double bond but why do br dissapear
3aii why does the 4th carbon have Ch3 whereas the last carbon on the original molecule have ch2.
2a is understand the double bond but why do br dissapear
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