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M1 exam question
Two particles P and Q of mass 4kg and 6kg respectively, are joined by a light inextensible string. Initially the particles are at rest on a rough horizontal plane with the string taut.The coefficient of friction between each particle and the plane is 2/7. A constant force of magnitude 40N is then applied to Q.
a) Show that the acceleration of Q is 1.2ms^-2
b) Calculate the tension in the string when the system is moving.
c) State how you have used the information that the string is inextensible.
a) Show that the acceleration of Q is 1.2ms^-2
b) Calculate the tension in the string when the system is moving.
c) State how you have used the information that the string is inextensible.
dont u need the force? or am i missing something basic..
Sorry, force is 40N
The Chameleon
Two particles P and Q of mass 4kg and 6kg respectively, are joined by a light inextensible string. Initially the particles are at rest on a rough horizontal plane with the string taut.The coefficient of friction between each particle and the plane is 2/7. A constant force of magnitude 40N is then applied to Q.
a) Show that the acceleration of Q is 1.2ms^-2
b) Calculate the tension in the string when the system is moving.
c) State how you have used the information that the string is inextensible.
a) Show that the acceleration of Q is 1.2ms^-2
b) Calculate the tension in the string when the system is moving.
c) State how you have used the information that the string is inextensible.
Apply "resultant Force=ma" to each particle
for P:
F=ma
40 -T- uR = 6a
uR=2/7 * 6g
=> 40-T - (/7 * 6g) = 6a ..........(1)
for Q:
T - (2/7 * 4g) = 4a
uR=2/7 * 4g
T - (2/7 * 4g) = 4a.......................(2)
(1) + (2) to eliminate T
=> 40 - 2/7*6g -2/7*4g = 10a
a=1.2 ms^-2
then subst a into either (1) or (2) for T = 16N
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