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In the combustion of methane:

CH4 + 2O2 → CO2 + 2H2O

What is the maximum mass of water that could be produced when reacting 48g of methane with 48g of oxygen?

Reply 1

Ec0108

Work out stoichiomertry

(edited 3 years ago)

Reply 2

Sophhhowa

Work out which one is the limiting reactant and the number of moles of this reactant. Use the molar ratio shown in the equation to find the moles of water produced. Mass= moles x 18

Reply 3

username5306262

Original post by Sophhhowa

Work out which one is the limiting reactant and the number of moles of this reactant. Use the molar ratio shown in the equation to find the moles of water produced. Mass= moles x 18

which one is limiting since they have equal masses

Reply 4

charco

Study Forum Helper

Original post by JellyInMyBelly

which one is limiting since they have equal masses

Limiting reagent does not depend on mass. It depends on the relative number of moles present and the stoichiometry of the equation.

Reply 5

username5306262

Original post by charco

Limiting reagent does not depend on mass. It depends on the relative number of moles present and the stoichiometry of the equation.

so for the question I posted how would you work out the limiting reagent ... the video isn't very helpful unless I am missing something

Reply 6

charco

Study Forum Helper

Original post by JellyInMyBelly

so for the question I posted how would you work out the limiting reagent ... the video isn't very helpful unless I am missing something

Calculate the MOLES of each reagent.

Then see from the stoichiometry of the reaction how many moles of one reagent should react with another.

The reagent that gets used up first is the limiting reagent and this is used to find out how many moles, and hence how much mass, of the products are formed.