How is baryon number conserved in alpha decay

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LeLivre
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It's all in the title
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PL1234
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I don’t know how correct this is but baryons consist of neutrons and protons.
So in alpha the total number of nucleons is constant hence the number of baryons is constant.
Idrk tbh
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Eimmanuel
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The following website provides the info that you are required to know to answer your question.
https://web.pa.msu.edu/courses/1998s...ar/decays.html
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Eimmanuel
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(Original post by Synergy_)
In the beta minus decay, the net process is



Both electron and anti-neutrino have no baryon number while both neutron and proton have a baryon number of 1 each.

So the baryon number is conserved for the beta minus decay.
OP is asking for alpha decay NOT beta minus decay.
But it is a good example to illustrate the conservation of Baryon number.
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username5301604
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(Original post by Eimmanuel)
OP is asking for alpha decay NOT beta minus decay.
But it is a good example to illustrate the conservation of Baryon number.
Hahaha, yeah I misread the title. I just realized this and deleted my post.
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Eimmanuel
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(Original post by Synergy_)
Hahaha, yeah I misread the title. I just realized this and deleted my post.
Maybe you can amend to answer the question instead of deleting it.
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username5301604
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Write a nuclear equation for the decay:

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X has proton number Z and nucleon number A
Y has proton number Z-2 and nucleon number A-4
He has proton number 2 and nucleon number 4

So, the baryon number remains the same.


Note:

  • The number of baryons: protons and neurons
  • The number of nucleons is equal on either side and therefore there is no change at all.
  • Each nucleon has a baryon number of +1;
  • Which means that the baryon number is conserved on both sides.


Hope that helped
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