It is given that f(x)=sin(x+30)+cos(x+60)
a) show that f(x)=cosx, hence show that f(4x)+4f(2x) = Acos^4x-B
b) determine the greatest and least values of 1/f(4x)+4f(2x)+7 as x varies
c) solve the equation, sin(12a+30)+cos(12a+60)+4sin(6a+30)+4cos(6a+60)=1 for 0<a<60
I have worked out part a as A=8 and B=3, which is correct, however I am struggling to find a starting point for both parts b and c, any ideas?