pondering-soul
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so I'm doing a question on optical isomers and I've come across this molecule 2-chlorobutane. I get how to draw the structural/display formula etc. but when it comes to the 3d structure I struggle.

I understand you need to use the VSEPR theoryImage


In the molecule, the chiral carbon has no lone pairs and 4 bonds so you would draw it tetrahedral right? But how do you tell whether the H and Cl is away or towards you (which one is dashed and which one is black)?? If you look in the 2nd attached file, I'm basically asking whether the H and the Cl can swap over, Cl being dashed and H being the other. If no why?

thanks for any help in advance I appreciate it
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Pigster
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(Original post by pondering-soul)
I'm basically asking whether the H and the Cl can swap over, Cl being dashed and H being the other.
Both versions exist.

We refer to them as optical isomers of each other, but I guess you know that since you mentioned 'chiral carbon'.
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pondering-soul
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(Original post by Pigster)
Both versions exist.

We refer to them as optical isomers of each other, but I guess you know that since you mentioned 'chiral carbon'.
wait so if you look at the mark scheme that my teacher drew, if I were to swap the Cl and the H atom with each other on only one side, they would be identical molecules again (not optical isomers) ??
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pondering-soul
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(Original post by Pigster)
Both versions exist.

We refer to them as optical isomers of each other, but I guess you know that since you mentioned 'chiral carbon'.
oh **** I visualised it in my head swapping them over, you're right thanks alot bro appreciate it
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