deviany
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please help me
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deviany
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deviany
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Size:  56.5 KB I already differentiate it then i have no idea the next step... i mean the qs said its parallel to x axis so there is possibility that y=0 but i dont know wht should i do
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Plücker
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(Original post by deviany)
Name:  image-d551abc8-f889-4508-ab4f-e650c0d8df0c163752749-compressed.jpg.jpeg
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Size:  56.5 KB I already differentiate it then i have no idea the next step... i mean the qs said its parallel to x axis so there is possibility that y=0 but i dont know wht should i do
"where a is a non-zero constant".
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deviany
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so -2xy-y^2=0 and i change y to 0. and since a is non zero constant so x will be a?
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(Original post by deviany)
so -2xy-y^2=0 and i change y to 0. and since a is non zero constant so x will be a?
No, y cannot be zero. If y=0 then a=0 and you are told that a is not zero.
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deviany
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then what should i do?
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(Original post by deviany)
then what should i do?
You have \frac{dy}{dx}=0 \Rightarrow y(y+2x)=0?

You know y is not zero, so...
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deviany
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then it would be 2x=-y
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(Original post by deviany)
then it would be 2x=-y
Yes. Any point where the tangent is parallel to the x axis must be on the line y = - 2x and also on the original curve. Can you continue from there?
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yes thank u so much
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(Original post by deviany)
yes thank u so much
You're welcome.
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