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    Eier and Totally Tom are correct. Otherwise my quadratic doesnt make sense and exam questions aren't often wrong.
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    The answer is Gary. This is all.
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    Maths people:

    So whats the integral between infinity and zero of e^[-(x^2)]? Easy convert to polars, do the double integral over dr and d(theta)...gives you root pi on two

    And the negative of two squared? errrrrrrrr....hmm
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    5...
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    look at the context though - it's -2 going into a quadratic so it would be (-2)^2 rather than the alternative -(2^2)
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    (Original post by Ramadulla)
    Seriously -- who gives a ****? I'm being honest. I know that my post isn't helpful, but this is one of these controversial topics. Do you not understand, OP, that you will NOT get a definite answer. Even people on TSR can't, and we're supposedly the 'top notch students'.
    The definite answer is -4. This thread annoys me. I prefer term time...
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    Normally I'd suggest making a poll but then that would probably give us the wrong answer.

    -4 from a fourth year university mathematician.
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    (Original post by barry_4_england)
    The definite answer is -4. This thread annoys me. I prefer term time...
    It's 4.
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    lol this is an absolutely immense trolling effort, good job.
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    -4
    simple maths
    i am shocked and horrified how many people dont know the correct answer, and indded how many are so confident in their wrong answer
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    hmm - I still say it's a unary minus but I'm now thinking (without the context) that that could apply to the result of the exponentiation, and that being the case I can certainly see how it could be taken in two ways. However once you've got the context I don't see any ambiguity

    Apologies if I jumped in a bit quick there
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    (Original post by jennyng2000)
    -4
    simple maths
    On my second post, i put it into context, it's 4.
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    ARGH, the answer to the thread title is -4.
    In context, which wasn't originally clear but was quickly explained by the OP....substituing -2 into a quadratic for a graph, -2 into x^2 gives 4.
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    (Original post by LearningMath)
    It's 4.
    It's not. .
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    (Original post by LearningMath)
    On my second post, i put it into context, it's 4.
    am i missing something? minus 2 times 2, ie -2 x 2, is -4
    how is that wrong?
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    (Original post by LearningMath)
    On my second post, i put it into context, it's 4.
    You're not substituting -2 into x^2 - you should be substituting 2 into -x^2 which is, of course, negative.
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    i.
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    (Original post by Gaz031)
    You're not substituting -2 into x^2 - you should be substituting 2 into -x^2 which is, of course, negative.
    weeeeee here we go again!
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    Okay, I'm closing this. I can't see everybody coming to a conclusion any time soon.
 
 
 

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