at equilibrium, you know that 1 mole of each will decompose (whichever direction the reaction is going). so for the backwards reaction, 1 mole of C2H5OH will produce 1 mole of C2H4 and H20.
to find how much 1 mole is, you subtract how many moles of products minus reactants. so, 5-1.85, as you started with 5, and the equation states that 1 mole is used to produce 1 mole of the C2H4 so it is used up from the 5. as the H2O and the C2H4 are the same molar ratios, the same amount of each are produced. therefore
remember, you don’t subtract the 1.85 twice from the 5, as the equation states that only one mole is used of the C2H5OH to make two moles of product. hope this helps if you haven’t figured it out already
at equilibrium, you know that 1 mole of each will decompose (whichever direction the reaction is going). so for the backwards reaction, 1 mole of C2H5OH will produce 1 mole of C2H4 and H20.
to find how much 1 mole is, you subtract how many moles of products minus reactants. so, 5-1.85, as you started with 5, and the equation states that 1 mole is used to produce 1 mole of the C2H4 so it is used up from the 5. as the H2O and the C2H4 are the same molar ratios, the same amount of each are produced. therefore
remember, you don’t subtract the 1.85 twice from the 5, as the equation states that only one mole is used of the C2H5OH to make two moles of product. hope this helps if you haven’t figured it out already
But if they are in the same ratio, surely c2h5oh will be 1.85?
But if they are in the same ratio, surely c2h5oh will be 1.85?
no, because the original amount of moles put IN is 5. the reaction is the backwards reaction so “1 mole” (in terms of the reaction ratio) is USED. 1.85 is USED, not made, no amount of c2h5oh is made in this reaction. therefore as 1 mole is used you subtract one mole (1.85) from the original amount to produce 3.15