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Integration problem

Right, having not done calculus since May I am a bit rusty to say the least.

I've been given the following problem: http://i206.photobucket.com/albums/bb3/isurfhawaii/calc.jpg?t=1220035577

I think I ought to rewrite tan^2 x as sec^2 x - 1 but I also thought of rewriting it as (sinx/cosx)^2. I'm lost either way I try it :p:

Forgive my lack of LaTeX, I don't know the codes.
sec2x−1sec^2x-1
can be easily integrated. Just think of a suitable antiderivative.

Hint: d/dx (tan x) = ?
Reply 2
Avatar for D-Day
D-Day
OP
10
Luckily that's a fairly easy one. tan x - x. I really ought to refresh my memory of all the others :>.<:
Reply 3
Avatar for D-Day
D-Day
OP
10
Come on, nota. Got to be more on the ball than that :rolleyes:

:p:

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