I don't understand this question, can anyone pls help😁😋

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vanessa_del
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A team of 7 is chosen travels to a match in 2 cars. A group of 4 travel in one car and a group of 3 travel in the other car.
In how many different ways can the team of 7 be divided into a group of 4 and a group of 3?
Last edited by vanessa_del; 6 days ago
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theJoyfulGeek
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(Original post by vanessa_del)
A team of 7 is chosen travels to a match in 2 cars. A group of 4 travel in one car and a group of 3 travel in the other car.
In how many different ways can the team of 7 be divided into a group of 4 and a group of 3?
So, you're choosing a group of 4 people from 7 people (and 3 are left over).
7C4, as order doesn't matter.

7C4 = 7!/4!3! = 7*6*5/3*2 = 35

So 35 ways of choosing the first 4, so a total of 35 ways.

(If you do 7C3, you also end up with 35).
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vanessa_del
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(Original post by theJoyfulGeek)
So, you're choosing a group of 4 people from 7 people (and 3 are left over).
7C4, as order doesn't matter.

7C4 = 7!/4!3! = 7*6*5/3*2 = 35

So 35 ways of choosing the first 4, so a total of 35 ways.

(If you do 7C3, you also end up with 35).
So is the answer 35 😃
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vanessa_del
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(Original post by theJoyfulGeek)
So, you're choosing a group of 4 people from 7 people (and 3 are left over).
7C4, as order doesn't matter.

7C4 = 7!/4!3! = 7*6*5/3*2 = 35

So 35 ways of choosing the first 4, so a total of 35 ways.

(If you do 7C3, you also end up with 35).
So is the answer 35 😄
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theJoyfulGeek
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(Original post by vanessa_del)
So is the answer 35 😃
Yep! (Unless I've messed up somewhere due to my lack of calculator).
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vanessa_del
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(Original post by theJoyfulGeek)
Yep! (Unless I've messed up somewhere due to my lack of calculator).
Thank you so much for the help 😋
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theJoyfulGeek
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(Original post by vanessa_del)
Thank you so much for the help 😋
No problem!
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