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    • Thread Starter

    I have this equation: 3x²y+6xy²+15xy that I need to factorise but I am unsure/have forgot how to do it.

    Can anyone on TSR help me please?

    Take out xy as a factor?

    3xy(x + 2y + 5)
    • Thread Starter

    Thank you very much, simple now I look back on it.

    To factorise it, you need to spot a common factor (which can be a letter or a number) of each of the three terms. In this case, there are more than one of these factors. You need to take each one out of each term, and put it before the bracket encompassing the whole thing.

    I'll give you a similar example to show how it's done:
    xyz + y^2z + yz
    Notice that there's a y in each term. If you factor this y out, you get
    y(xz + yz + z)
    Also notice that, within the bracket, there's a z in each term, which can too be factored out, giving:
    yz(x + y + 1) (notice how the z becomes a 1, rather than disappearing entirely.)
    which is the fully factored version of the example, as nothing else will factor out.

    Hope that helped, reckon you can do yours now?

    EDIT: the thread always finishes before I have time to type my replies
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Updated: August 30, 2008

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