# As level stats venn diagram help

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#1
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1 month ago
#2
(Original post by flappyduck21)
Where was the last place you saw them
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#3
(Original post by flappyduck21)
(Original post by Eri Brace)
Where was the last place you saw them
On the M5 evading a police chase 😐 (picture of q is below 😉)
Last edited by flappyduck21; 1 month ago
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#4
(Original post by flappyduck21)
Here is the question
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1 month ago
#5
You got p right, it's 0.2 coz A is 0.4 in total.

For q you know P(A or B) is 0.7 so everything in both circles must add to 0.7 and you know the total of circle A is 0.4

So q is 0.7-0.4
q=0.3
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1 month ago
#6
P=0.2
q=0.3
r=0.2
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#7
(Original post by gyuigygh)
You got p right, it's 0.2 coz A is 0.4 in total.

For q you know P(A or B) is 0.7 so everything in both circles must add to 0.7 and you know the total of circle A is 0.4

So q is 0.7-0.4
q=0.3
Hmm i understand where ur coming from.. But I got 0.3 in my working and then i used that and took it away from the value of p (0.2) and got 0.1 for q...

The reason i took it away was to get the value of q on its own.. Or does q represent the whole circle??
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#8
(Original post by Eri Brace)
P=0.2
q=0.3
r=0.2
Does q represent the value of the whole circle
?
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1 month ago
#9
(Original post by flappyduck21)
Does q represent the value of the whole circle
?
No just the blue bit
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1 month ago
#10
(Original post by flappyduck21)
Hmm i understand where ur coming from.. But I got 0.3 in my working and then i used that and took it away from the value of p (0.2) and got 0.1 for q...

The reason i took it away was to get the value of q on its own.. Or does q represent the whole circle??
How did you get 0.3?
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#11
(Original post by gyuigygh)
How did you get 0.3?
So P(A or b) = p(a) + p(b)
0.7. = 0.4. + p(b)

Hence 0.7 -0.4 = 0.3 for p(b)
Then i did q = 0.3 -0.2 = 0.1
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1 month ago
#12

Also, this formula(in red) is only for mutually exclusive events (circles that are not touching as mutually exclusive means impossible to happen at same time so no overlap)

A and B are not mutually exclusive to each other as there is overlap.
A and C are mutually exclusive.
B and C are mutually exclusive.

So you cannot use that formula for P(A or B) ,
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#13
(Original post by gyuigygh)

Also, this formula(in red) is only for mutually exclusive events (circles that are not touching as mutually exclusive means impossible to happen at same time so no overlap)

A and B are not mutually exclusive to each other as there is overlap.
A and C are mutually exclusive.
B and C are mutually exclusive.

So you cannot use that formula for P(A or B) ,
Ahh yeh your right! I inferred from what the question said 'the probability of a and b is 0.7' 😅
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1 month ago
#14
(Original post by flappyduck21)
So P(A or b) = p(a) + p(b)
0.7. = 0.4. + p(b)

Hence 0.7 -0.4 = 0.3 for p(b)
Then i did q = 0.3 -0.2 = 0.1
That formula is for mutually exclusive events use
P(A or B) =P(A) +P(B) - P(A intersect B)
if you wanna use a formula
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#15
(Original post by gyuigygh)
That formula is for mutually exclusive events use
P(A or B) =P(A) +P(B) - P(A intersect B)
if you wanna use a formula
Ahh yeh that looks good makes sense now! Thanks for the help 😊
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1 month ago
#16
Np
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#17
Got another

(Original post by gyuigygh)
Np
Got one more question that I need help in.. Mind having a look?
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1 month ago
#18
(Original post by flappyduck21)
Got another

Got one more question that I need help in.. Mind having a look?
Go on then, the night is still young
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#19
(Original post by gyuigygh)
Np

(Original post by gyuigygh)
Go on then
0
1 month ago
#20
For a multiply them I think.
For b have a go urself first
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