deviany
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number 3 part 2 asked to use iterative formula right
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i tried to use it as u can see from x1 to x9 but i cannot find 2.12... which part im makin mistake?
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Sam_R9
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(Original post by deviany)
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number 3 part 2 asked to use iterative formula right
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i tried to use it as u can see from x1 to x9 but i cannot find 2.12... which part im makin mistake?
For the first part, you must use x = 2 and x = 3.
Substitute those values in the equation given and you'll notice a sign change.
The change in sign indicates that there is a root in the given interval.

For the second part, use x = 2 for the iteration formula and keep working till you get the similar answer to 3 d.p.
This website could help you:
https://www.bbc.co.uk/bitesize/guide...0and%20so%20on.

Hope this helps
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Plücker
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(Original post by deviany)
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number 3 part 2 asked to use iterative formula right
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i tried to use it as u can see from x1 to x9 but i cannot find 2.12... which part im makin mistake?
As mentioned Sam_R9 you only need to calculated two values for part i of the question.

In part ii you appear to have calculated x_2= e^{x_1}-x_1+2.

You should be doing x_2=e^{-x_1}+2 as given in the question.
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