# SUVAT question mechanics

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I have a question where I have s,v and a. I need to find t. I used s = vt - 1/2at^2 and got two answers. The book used v^2 = u" +2as to find u then used v= u + at to find t, so got one answer, which I also got as one of my two. My question is - are there certain times you use certain equations? Like obviously, if it said what are the possible value(s) you'd use the one that gives a quadratic? If not - then why did I get two answers? The situation in question is about a car travelling from A to C in a certain time, accelerating.

Edit: Grammar

Edit: Grammar

Last edited by EmRep13; 2 months ago

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(Original post by

Can you send a picture of the question? Just curious about it

**Joseph Green**)Can you send a picture of the question? Just curious about it

A car is travelling along a straight horizontal road with constant acceleration. The car passes over three consecutive points A, B and C where AB = 100m and BC = 300m. The speed of the car at B is 14m/s and the speed of the car at C is 20m/s. Find:

a) The acceleration of the car

b) the time taken for the car to travel from A to C

The answers are 0.34ms^-2 and 25.5 s (3sf) respectively. Typed out because of aforementioned laziness. Thanks!

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#4

So from double checking what I noticed is that using the vt - 1/2at^2 typically leads to these kinds of situations where you get 2 possible answers. The reason is the minus sign. A good way to think about it using your moving car is to switch it to a projectile being thrown up into the air. The acceleration is negative and it ends up passing through a chosen height twice (except for the apex of the path). Although it seems silly, that's what is essentially being drawn when you use the vt - 1/2at^2 equation. It does happen if you use the ut + 1/2at^2 where your acceleration is negative originally but it is easier to perceive that way. In these cases where you get 2 possible answers the idea is to choose the more reasonable answer. The reason the textbook used their method was it made it faster to calculate the overall time as opposed to having to calculate 2 different times and summing them together. I hope this helps. If not feel free to dm me and I'll try draw some examples

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(Original post by

So from double checking what I noticed is that using the vt - 1/2at^2 typically leads to these kinds of situations where you get 2 possible answers. The reason is the minus sign. A good way to think about it using your moving car is to switch it to a projectile being thrown up into the air. The acceleration is negative and it ends up passing through a chosen height twice (except for the apex of the path). Although it seems silly, that's what is essentially being drawn when you use the vt - 1/2at^2 equation. It does happen if you use the ut + 1/2at^2 where your acceleration is negative originally but it is easier to perceive that way. In these cases where you get 2 possible answers the idea is to choose the more reasonable answer. The reason the textbook used their method was it made it faster to calculate the overall time as opposed to having to calculate 2 different times and summing them together. I hope this helps. If not feel free to dm me and I'll try draw some examples

**Joseph Green**)So from double checking what I noticed is that using the vt - 1/2at^2 typically leads to these kinds of situations where you get 2 possible answers. The reason is the minus sign. A good way to think about it using your moving car is to switch it to a projectile being thrown up into the air. The acceleration is negative and it ends up passing through a chosen height twice (except for the apex of the path). Although it seems silly, that's what is essentially being drawn when you use the vt - 1/2at^2 equation. It does happen if you use the ut + 1/2at^2 where your acceleration is negative originally but it is easier to perceive that way. In these cases where you get 2 possible answers the idea is to choose the more reasonable answer. The reason the textbook used their method was it made it faster to calculate the overall time as opposed to having to calculate 2 different times and summing them together. I hope this helps. If not feel free to dm me and I'll try draw some examples

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#6

When you’re choosing which equation to use you should list out what the question has already given you.

Like:

S=

U=

V=

A=

T=

Your question will always give 3 of the above, the other one is the one you’re calculating and the last one is irrelevant.

So for part a) you’re given s,u and v. You need to calculate a. The irrelevant one is t so you find an equation that does not involve t. The only one is v^2= u^2 +2as which is the accurate formula to be used.

For part b) you have all of the components so you can really use any equation to calculate the time but since there is a possibility of getting part a) incorrect you should choose an equation that doesn’t involve acceleration. ( you said the book used v=u+at but personally I would use s=1/2(u+v)t

This method helps answer any suvat question for a level and gcse maths.

Hope this helps and if you’ve got any other questions let me know x

Like:

S=

U=

V=

A=

T=

Your question will always give 3 of the above, the other one is the one you’re calculating and the last one is irrelevant.

So for part a) you’re given s,u and v. You need to calculate a. The irrelevant one is t so you find an equation that does not involve t. The only one is v^2= u^2 +2as which is the accurate formula to be used.

For part b) you have all of the components so you can really use any equation to calculate the time but since there is a possibility of getting part a) incorrect you should choose an equation that doesn’t involve acceleration. ( you said the book used v=u+at but personally I would use s=1/2(u+v)t

This method helps answer any suvat question for a level and gcse maths.

Hope this helps and if you’ve got any other questions let me know x

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#7

(Original post by

I thought that but since the acceleration is positive, surely the car doesn't double back? Also your last sentence - "summing them together" - what do you mean?

**EmRep13**)I thought that but since the acceleration is positive, surely the car doesn't double back? Also your last sentence - "summing them together" - what do you mean?

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#8

**EmRep13**)

I thought that but since the acceleration is positive, surely the car doesn't double back? Also your last sentence - "summing them together" - what do you mean?

(Original post by

When you’re choosing which equation to use you should list out what the question has already given you.

Like:

S=

U=

V=

A=

T=

Your question will always give 3 of the above, the other one is the one you’re calculating and the last one is irrelevant.

So for part a) you’re given s,u and v. You need to calculate a. The irrelevant one is t so you find an equation that does not involve t. The only one is v^2= u^2 +2as which is the accurate formula to be used.

For part b) you have all of the components so you can really use any equation to calculate the time but since there is a possibility of getting part a) incorrect you should choose an equation that doesn’t involve acceleration. ( you said the book used v=u+at but personally I would use s=1/2(u+v)t

This method helps answer any suvat question for a level and gcse maths.

Hope this helps and if you’ve got any other questions let me know x

**Zoeva123**)When you’re choosing which equation to use you should list out what the question has already given you.

Like:

S=

U=

V=

A=

T=

Your question will always give 3 of the above, the other one is the one you’re calculating and the last one is irrelevant.

So for part a) you’re given s,u and v. You need to calculate a. The irrelevant one is t so you find an equation that does not involve t. The only one is v^2= u^2 +2as which is the accurate formula to be used.

For part b) you have all of the components so you can really use any equation to calculate the time but since there is a possibility of getting part a) incorrect you should choose an equation that doesn’t involve acceleration. ( you said the book used v=u+at but personally I would use s=1/2(u+v)t

This method helps answer any suvat question for a level and gcse maths.

Hope this helps and if you’ve got any other questions let me know x

0

reply

(Original post by

Summing together is just a fancy way of saying adding. And like I said it's really odd to think about but remember the minus sign makes all the difference here when it comes to drawing the parabola and extrapolating results from it. It's true that the acceleration is positive and it doesn't double back on the first position but the maths works out such that it appears to,since the parabola appears somewhere else on a graph etc etc. What you should gather from this example is that watching out for negative signs and making an appropriate assumption will save you 100000000000000 marks in exams

**Joseph Green**)Summing together is just a fancy way of saying adding. And like I said it's really odd to think about but remember the minus sign makes all the difference here when it comes to drawing the parabola and extrapolating results from it. It's true that the acceleration is positive and it doesn't double back on the first position but the maths works out such that it appears to,since the parabola appears somewhere else on a graph etc etc. What you should gather from this example is that watching out for negative signs and making an appropriate assumption will save you 100000000000000 marks in exams

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#10

(Original post by

Yeah I know! I just don't understand at what point you'd add two answers together when doing the quadratic thing? Ah - so the maths gives you two answers but in reality only one is right, unless you're using an situation with deacceleration where it would eventually double back.

**EmRep13**)Yeah I know! I just don't understand at what point you'd add two answers together when doing the quadratic thing? Ah - so the maths gives you two answers but in reality only one is right, unless you're using an situation with deacceleration where it would eventually double back.

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reply

**Zoeva123**)

When you’re choosing which equation to use you should list out what the question has already given you.

Like:

S=

U=

V=

A=

T=

Your question will always give 3 of the above, the other one is the one you’re calculating and the last one is irrelevant.

So for part a) you’re given s,u and v. You need to calculate a. The irrelevant one is t so you find an equation that does not involve t. The only one is v^2= u^2 +2as which is the accurate formula to be used.

For part b) you have all of the components so you can really use any equation to calculate the time but since there is a possibility of getting part a) incorrect you should choose an equation that doesn’t involve acceleration. ( you said the book used v=u+at but personally I would use s=1/2(u+v)t

This method helps answer any suvat question for a level and gcse maths.

Hope this helps and if you’ve got any other questions let me know x

1

reply

Report

#12

**EmRep13**)

Yeah I know! I just don't understand at what point you'd add two answers together when doing the quadratic thing? Ah - so the maths gives you two answers but in reality only one is right, unless you're using an situation with deacceleration where it would eventually double back.

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#13

(Original post by

The maths should only actually give you one answer if your method is correct. The car is moving in a straight line so the velocity does not change hence is always positive. If the direction changes you get positive and negative which can then give you 2 answers.

**Zoeva123**)The maths should only actually give you one answer if your method is correct. The car is moving in a straight line so the velocity does not change hence is always positive. If the direction changes you get positive and negative which can then give you 2 answers.

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#14

(Original post by

Yeah - I was going to type it out for context but felt a bit lazy . Guess I have to now!

A car is travelling along a straight horizontal road with constant acceleration. The car passes over three consecutive points A, B and C where AB = 100m and BC = 300m. The speed of the car at B is 14m/s and the speed of the car at C is 20m/s. Find:

a) The acceleration of the car

b) the time taken for the car to travel from A to C

The answers are 0.34ms^-2 and 25.5 s (3sf) respectively. Typed out because of aforementioned laziness. Thanks!

**EmRep13**)Yeah - I was going to type it out for context but felt a bit lazy . Guess I have to now!

A car is travelling along a straight horizontal road with constant acceleration. The car passes over three consecutive points A, B and C where AB = 100m and BC = 300m. The speed of the car at B is 14m/s and the speed of the car at C is 20m/s. Find:

a) The acceleration of the car

b) the time taken for the car to travel from A to C

The answers are 0.34ms^-2 and 25.5 s (3sf) respectively. Typed out because of aforementioned laziness. Thanks!

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(Original post by

What was the value of u that they worked out?

**Joseph Green**)What was the value of u that they worked out?

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#16

(Original post by

+_ sqrt 128 or +- 8 sqrt 3 and then they decided to use +8sqrt3 assuming the car didn't accelerate reversing backwards

**EmRep13**)+_ sqrt 128 or +- 8 sqrt 3 and then they decided to use +8sqrt3 assuming the car didn't accelerate reversing backwards

The blue quadratic is the s = ut + 1/2at^2 formula and the red is the s = vt - 1/2at^2.

As you can see, the blue one has a positive and negative root, which represent the time solution we are after. The red has 2 positive roots which also both represent the time solutions. The difference is that the red one quite literally creates a false positive. I've also found the intersection between these 2 graphs to show you that the answer is indeed that 25.5 and using either method that involves the quadratic suvat equations will result in the right solution provided you choose the right answer.

I hope this helps a little

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(Original post by

Using the value that they got for u and plugging it into the s = ut + 1/2at^2 you get the same answer and I'll show you.

The blue quadratic is the s = ut + 1/2at^2 formula and the red is the s = vt - 1/2at^2.

As you can see, the blue one has a positive and negative root, which represent the time solution we are after. The red has 2 positive roots which also both represent the time solutions. The difference is that the red one quite literally creates a false positive. I've also found the intersection between these 2 graphs to show you that the answer is indeed that 25.5 and using either method that involves the quadratic suvat equations will result in the right solution provided you choose the right answer.

I hope this helps a little

**Joseph Green**)Using the value that they got for u and plugging it into the s = ut + 1/2at^2 you get the same answer and I'll show you.

The blue quadratic is the s = ut + 1/2at^2 formula and the red is the s = vt - 1/2at^2.

As you can see, the blue one has a positive and negative root, which represent the time solution we are after. The red has 2 positive roots which also both represent the time solutions. The difference is that the red one quite literally creates a false positive. I've also found the intersection between these 2 graphs to show you that the answer is indeed that 25.5 and using either method that involves the quadratic suvat equations will result in the right solution provided you choose the right answer.

I hope this helps a little

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reply

Report

#18

(Original post by

I have a question where I have s,v and a. I need to find t. I used s = vt - 1/2at^2 and got two answers. The book used v^2 = u" +2as to find u then used v= u + at to find t, so got one answer, which I also got as one of my two. My question is - are there certain times you use certain equations? Like obviously, if it said what are the possible value(s) you'd use the one that gives a quadratic? If not - then why did I get two answers? The situation in question is about a car travelling from A to C in a certain time, accelerating.

Edit: Grammar

**EmRep13**)I have a question where I have s,v and a. I need to find t. I used s = vt - 1/2at^2 and got two answers. The book used v^2 = u" +2as to find u then used v= u + at to find t, so got one answer, which I also got as one of my two. My question is - are there certain times you use certain equations? Like obviously, if it said what are the possible value(s) you'd use the one that gives a quadratic? If not - then why did I get two answers? The situation in question is about a car travelling from A to C in a certain time, accelerating.

Edit: Grammar

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(Original post by

The book should have got two answers for u (plus and minus the square root), and discounted one.

**RogerOxon**)The book should have got two answers for u (plus and minus the square root), and discounted one.

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