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maths help

there are eight colours of smarties which normally occur in equal proportions: red, orange, yellow, green, blue, purple, pink and brown.
daisy's mother gives each of her children 16 smarties. daisy says that the blue ones are much nicer than the rest and is very upset when she receives less than her fair share of them.

a) how many blue smarties did daisy expect to get?

b)what was the probability that she would receive fewer blue ones than she expected?

c) what was the probability that she would receive more blue ones than she expected?
Original post by help_me_learn
there are eight colours of smarties which normally occur in equal proportions: red, orange, yellow, green, blue, purple, pink and brown.
daisy's mother gives each of her children 16 smarties. daisy says that the blue ones are much nicer than the rest and is very upset when she receives less than her fair share of them.

a) how many blue smarties did daisy expect to get?

b)what was the probability that she would receive fewer blue ones than she expected?

c) what was the probability that she would receive more blue ones than she expected?

There are 8 colours so P(blue) = 1/8
So you have n=16 and p=1/8.
a) The expected value is np.
Is that enough to get you started?

As you have probably realised, it's better to post maths questions in the maths forum. I'm not sure many helpers there look anywhere else much.
Original post by Plücker
There are 8 colours so P(blue) = 1/8
So you have n=16 and p=1/8.
a) The expected value is np.
Is that enough to get you started?

As you have probably realised, it's better to post maths questions in the maths forum. I'm not sure many helpers there look anywhere else much.

ahh thank you so much! only problem is...for c) do i have to work out the sum of the probability between x= 3 to 16?
and thank you for the advice!
Original post by help_me_learn
ahh thank you so much! only problem is...for c) do i have to work out the sum of the probability between x= 3 to 16?
and thank you for the advice!

P(X>a)=1−P(X≤a)P(X>a)=1-P(X \le a)

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