deviany
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how to do number 15 part 2??? how can x^3-8x-13 be (2x^3+2)/(3x^2-2)?
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Unlucki
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(Original post by deviany)
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how to do number 15 part 2??? how can x^3-8x-13 be (2x^3+2)/(3x^2-2)?
If you multiply out the fraction, i.e. bring 3x^2-2 to the left and multiply it by the x, then rearrange, you should see that it gives you the original equation
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deviany
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(Original post by Unlucki)
If you multiply out the fraction, i.e. bring 3x^2-2 to the left and multiply it by the x, then rearrange, you should see that it gives you the original equation
what do u mean by multiply it by the x?
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mqb2766
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(Original post by deviany)
what do u mean by multiply it by the x?
As the previous post suggested, multiplying through by the denominator gives
x(3x^2-2) = 2x^3+2
Rearrange it and you get back to your original cubic equation.
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