# Circle Question

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#1

For A i got (3,-1)

then for B i got (x-3)^2 +(y+1)^2 = 15

then for c this is the one I'm not very sure about i got 5root 5
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#2
(Original post by Hollymae764)

For A i got (3,-1)

then for B i got (x-3)^2 +(y+1)^2 = 15

then for c this is the one I'm not very sure about i got 5root 5
can someone help me with the last one d because I don't understand how to do it. thank youu
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3 months ago
#3
(Original post by Hollymae764)

For A i got (3,-1)

then for B i got (x-3)^2 +(y+1)^2 = 15

then for c this is the one I'm not very sure about i got 5root 5
For b) have you checked it by subbing in a point? There is a small mistake.
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#4
(Original post by mqb2766)
For b) have you checked it by subbing in a point? There is a small mistake.
Should the 15 be 15^2
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3 months ago
#5
(Original post by Hollymae764)
can someone help me with the last one d because I don't understand how to do it. thank youu
C is right.
For D) you need to find RQ using pythagoras, then it's just simple trig.
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3 months ago
#6
(Original post by Hollymae764)
Should the 15 be 15^2
Yes, just put in one of the points to check if you're not sure.
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#7
(Original post by mqb2766)
C is right.
For D) you need to find RQ using pythagoras, then it's just simple trig.
Im confused, how do i used Pythagoras if the triangles not right angled
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3 months ago
#8
(Original post by Hollymae764)
Im confused, how do i used Pythagoras if the triangles not right angled
PQR is right angled (thales circle theorem).
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#9
I got the answer 41.8 is this correct
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3 months ago
#10
(Original post by Hollymae764)
I got the answer 41.8 is this correct
Looks about right, but it helps to see your working if possible (next time)?
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3 months ago
#11
(Original post by Hollymae764)
I got the answer 41.8 is this correct
A slightly different way would be to find angle PAR then half of that (exterior angle to an isosceles triangle). It would save calculating QR. Half of PAR would follow directly from the triangle used in part c).
I guess the model soln would do this as it's just one simple trig calculation
asin(2/3)
Last edited by mqb2766; 3 months ago
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