# A level chemistry question on partial pa/kp pls help

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Thread starter 10 months ago
#1
Got wrong.In mark scheme for b they do
71.6+(2x p(H2))=111
what's with the 2 times partial pressure of h2?....
Could someone please just explain how to do b and c?Thnks in advance ATTACHED FILE
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10 months ago
#2
(Original post by someusernamet)
Got wrong.In mark scheme for b they do
71.6+(2x p(H2))=111
what's with the 2 times partial pressure of h2?....
Could someone please just explain how to do b and c?Thnks in advance ATTACHED FILE
You have the expression correct.

You can see from the equation that mol(CO) = mol(H2), hence pp(H2) = pp(CO)

and the total pressure = sum the the partial pressures

p(tot) = pp(H2O) + pp(H2) + pp(CO)

111 = 71.6 + [2 x pp(H2)]

pp(H2) = 19.7
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