The Student Room Group

uncertainty

How do I calculate the uncertainty for this?

first row:
mass/kg:0.200 T/s:0.24 Uncertainty in T/s: 0.06 (T^2)/(s^2):0.06 Uncertainty in (T^2)/(s^2):?????

Second row:
mass/kg:0.400 T/s:0.35 Uncertainty in T/s: 0.06 (T^2)/(s^2):0.12 Uncertainty in (T^2)/(s^2):0.04

Third row:
mass/kg:0.600 T/s:0.42 Uncertainty in T/s: 0.06 (T^2)/(s^2):0.18 Uncertainty in (T^2)/(s^2):0.05

Fourth row:
mass/kg:0.800 T/s:0.44 Uncertainty in T/s: 0.06 (T^2)/(s^2):0.19 Uncertainty in (T^2)/(s^2):0.05
Reply 1
How do I calculate the uncertainty for this?

first row:
mass/kg:0.200 T/s:0.24 Uncertainty in T/s: 0.06 (T^2)/(s^2):0.06 Uncertainty in (T^2)/(s^2):?????

Second row:
mass/kg:0.400 T/s:0.35 Uncertainty in T/s: 0.06 (T^2)/(s^2):0.12 Uncertainty in (T^2)/(s^2):0.04

Third row:
mass/kg:0.600 T/s:0.42 Uncertainty in T/s: 0.06 (T^2)/(s^2):0.18 Uncertainty in (T^2)/(s^2):0.05

Fourth row:
mass/kg:0.800 T/s:0.44 Uncertainty in T/s: 0.06 (T^2)/(s^2):0.19 Uncertainty in (T^2)/(s^2):0.05
Reply 2
Hi again,
I am assuming there is no uncertainty in the mass (as I can't see it listed). What you want to do is calculate percentage uncertainty in T, uncertainty/value *100. To find uncertainty in T^2 at A-level we just double the percentage uncertainty in T and then return the percentage to an absolute value, by dividing by 100 and multiply by actual value.
Does this help? (unfortunately it takes a fair bit of time just going back and forward between percentage and absolute, but it is necessary!)
Reply 3
Original post by tande33
Hi again,
I am assuming there is no uncertainty in the mass (as I can't see it listed). What you want to do is calculate percentage uncertainty in T, uncertainty/value *100. To find uncertainty in T^2 at A-level we just double the percentage uncertainty in T and then return the percentage to an absolute value, by dividing by 100 and multiply by actual value.
Does this help? (unfortunately it takes a fair bit of time just going back and forward between percentage and absolute, but it is necessary!)

Honestly I don't understand, sorry. Could you rephrase this? Or give an example?
It's difficult to know, from what you have written here, what this is all about. More context needed.
But this may help.
The rule is
1) find the % uncertainty in the value
So 0.24 with an uncertainty of 0.06 is a % uncertainty of 100 x 0.06/0.24 = 25% (this seems much too high for an experimental value)
If you square a quantity, then you double the % uncertainty.
So in this case it becomes 50% (again, this would be too high in an experiment.)
Do the same for the other values.
You have posted this question twice. I have answered in the other post.
Reply 6
Original post by lege-lego
Honestly I don't understand, sorry. Could you rephrase this? Or give an example?

Are you familiar with calculating percentage uncertainty as if not, this is not going to make sense. But I'll try anyway.

Using 1st row as an example:

Step 1: Put absolute uncertainty in percentage uncertainty form, 0.06/0.24 *100= 25pc

Step 2: As we want uncertainty in T^x (where x is an integer, in this case 2) we multiply the uncertainty by x (2 in this case) to get 50 pc uncertainty.

Step 3: convert back to absolute uncertainty. As we have a percentage uncertainty of 50pc, we divide by 100, to get 0.5 and then multiply by the actual value of T^2, 0.06. This gives us a final answer of 0.03.

Is that any better? :smile:
Reply 7
Original post by tande33
Are you familiar with calculating percentage uncertainty as if not, this is not going to make sense. But I'll try anyway.

Using 1st row as an example:

Step 1: Put absolute uncertainty in percentage uncertainty form, 0.06/0.24 *100= 25pc

Step 2: As we want uncertainty in T^x (where x is an integer, in this case 2) we multiply the uncertainty by x (2 in this case) to get 50 pc uncertainty.

Step 3: convert back to absolute uncertainty. As we have a percentage uncertainty of 50pc, we divide by 100, to get 0.5 and then multiply by the actual value of T^2, 0.06. This gives us a final answer of 0.03.

Is that any better? :smile:

Thank you tande! I thought that 0.06 was the uncertainty and not the absolute uncertainty so it didn't make any sense.

Quick Reply

Latest