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Simple Harmonic Motion
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lege-lego
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A grandfather clock uses a simple pendulum to keep an accurate track of time. The seconds hand of the clock moves forward exactly one second each time it moves forward from A to C, and another second each time it moves from C to A.
Determine the length of the pendulum in a grandfather clock that would accurately tell the time. The average gravitational field strength (g) at the Earth's surface is 9.81 ms^(-2).
In this case A and C are the points of maximum amplitude/displacement. So the period would be 2 seconds and the frequency would be 0.5Hz.
But how am I supposed to work out the length???
Determine the length of the pendulum in a grandfather clock that would accurately tell the time. The average gravitational field strength (g) at the Earth's surface is 9.81 ms^(-2).
In this case A and C are the points of maximum amplitude/displacement. So the period would be 2 seconds and the frequency would be 0.5Hz.
But how am I supposed to work out the length???
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#2
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#2
(Original post by lege-lego)
A grandfather clock uses a simple pendulum to keep an accurate track of time. The seconds hand of the clock moves forward exactly one second each time it moves forward from A to C, and another second each time it moves from C to A.
Determine the length of the pendulum in a grandfather clock that would accurately tell the time. The average gravitational field strength (g) at the Earth's surface is 9.81 ms^(-2).
In this case A and C are the points of maximum amplitude/displacement. So the period would be 2 seconds and the frequency would be 0.5Hz.
But how am I supposed to work out the length???
A grandfather clock uses a simple pendulum to keep an accurate track of time. The seconds hand of the clock moves forward exactly one second each time it moves forward from A to C, and another second each time it moves from C to A.
Determine the length of the pendulum in a grandfather clock that would accurately tell the time. The average gravitational field strength (g) at the Earth's surface is 9.81 ms^(-2).
In this case A and C are the points of maximum amplitude/displacement. So the period would be 2 seconds and the frequency would be 0.5Hz.
But how am I supposed to work out the length???
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tande33
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#3
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#3
(Original post by lege-lego)
A grandfather clock uses a simple pendulum to keep an accurate track of time. The seconds hand of the clock moves forward exactly one second each time it moves forward from A to C, and another second each time it moves from C to A.
Determine the length of the pendulum in a grandfather clock that would accurately tell the time. The average gravitational field strength (g) at the Earth's surface is 9.81 ms^(-2).
In this case A and C are the points of maximum amplitude/displacement. So the period would be 2 seconds and the frequency would be 0.5Hz.
But how am I supposed to work out the length???
A grandfather clock uses a simple pendulum to keep an accurate track of time. The seconds hand of the clock moves forward exactly one second each time it moves forward from A to C, and another second each time it moves from C to A.
Determine the length of the pendulum in a grandfather clock that would accurately tell the time. The average gravitational field strength (g) at the Earth's surface is 9.81 ms^(-2).
In this case A and C are the points of maximum amplitude/displacement. So the period would be 2 seconds and the frequency would be 0.5Hz.
But how am I supposed to work out the length???
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lege-lego
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#4
(Original post by tande33)
T=2*pi* root (l/g). (this is at the bottom of the formula sheet) You know length and gravity so you can sub in T too and you have your answer!
T=2*pi* root (l/g). (this is at the bottom of the formula sheet) You know length and gravity so you can sub in T too and you have your answer!
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#5
(Original post by lege-lego)
thanks for this! I'm going to save this formula sheet haha
Also, thank you tande. This helped too!
thanks for this! I'm going to save this formula sheet haha
Also, thank you tande. This helped too!
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lege-lego
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tande33
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Stonebridge
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