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1ai) did they simplify the molar ratio
can i have 10Cl^- goes to 5Cl2 + 10e-
2a.) how am i suppose to form the equation and why did they times by 10 for the 250cm bit
4aii) i dont get why iron is 2+ how did they get that from
5) how will i know the oxidation state of Mg as i dont know the Oxidation state of S
7.) dont get
thanks
https://pmt.physicsandmathstutor.com...s%201%20QP.pdf
https://pmt.physicsandmathstutor.com...s%201%20MS.pdf
can i have 10Cl^- goes to 5Cl2 + 10e-
2a.) how am i suppose to form the equation and why did they times by 10 for the 250cm bit
4aii) i dont get why iron is 2+ how did they get that from
5) how will i know the oxidation state of Mg as i dont know the Oxidation state of S
7.) dont get
thanks
https://pmt.physicsandmathstutor.com...s%201%20QP.pdf
https://pmt.physicsandmathstutor.com...s%201%20MS.pdf
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#2
(Original post by Jshek)
1ai) did they simplify the molar ratio
can i have 10Cl^- goes to 5Cl2 + 10e-
2a.) how am i suppose to form the equation and why did they times by 10 for the 250cm bit
4aii) i dont get why iron is 2+ how did they get that from
5) how will i know the oxidation state of Mg as i dont know the Oxidation state of S
7.) dont get
thanks
https://pmt.physicsandmathstutor.com...s%201%20QP.pdf
https://pmt.physicsandmathstutor.com...s%201%20MS.pdf
1ai) did they simplify the molar ratio
can i have 10Cl^- goes to 5Cl2 + 10e-
2a.) how am i suppose to form the equation and why did they times by 10 for the 250cm bit
4aii) i dont get why iron is 2+ how did they get that from
5) how will i know the oxidation state of Mg as i dont know the Oxidation state of S
7.) dont get
thanks
https://pmt.physicsandmathstutor.com...s%201%20QP.pdf
https://pmt.physicsandmathstutor.com...s%201%20MS.pdf
2. a. You would have to know that dichromate ions turn to chromium(III) when they are reduced and iron turns to iron(III) when iron(II) is oxidised. The titration was carried out on a 25ml sample, but you need to determine the moles in 250ml.
4.a. (ii) It tells you iron(II) sulfide. The (II) means that the iron ions are in the +2 oxidation state and have a charge of 2+
5. Magnesium is in group 2. It does not have a variable oxidation state.
7. To answer this you need to know the reaction. The issue here is that sulfuric acid first displaces HI from an iodide, but it then oxidises it to iodine and in turn gets reduced to sulfur(IV oxide and even hydrogen sulfide.
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(Original post by charco)
1. a (i) Yes, you would simplify it.
2. a. You would have to know that dichromate ions turn to chromium(III) when they are reduced and iron turns to iron(III) when iron(II) is oxidised. The titration was carried out on a 25ml sample, but you need to determine the moles in 250ml.
4.a. (ii) It tells you iron(II) sulfide. The (II) means that the iron ions are in the +2 oxidation state and have a charge of 2+
5. Magnesium is in group 2. It does not have a variable oxidation state.
7. To answer this you need to know the reaction. The issue here is that sulfuric acid first displaces HI from an iodide, but it then oxidises it to iodine and in turn gets reduced to sulfur(IV oxide and even hydrogen sulfide.
1. a (i) Yes, you would simplify it.
2. a. You would have to know that dichromate ions turn to chromium(III) when they are reduced and iron turns to iron(III) when iron(II) is oxidised. The titration was carried out on a 25ml sample, but you need to determine the moles in 250ml.
4.a. (ii) It tells you iron(II) sulfide. The (II) means that the iron ions are in the +2 oxidation state and have a charge of 2+
5. Magnesium is in group 2. It does not have a variable oxidation state.
7. To answer this you need to know the reaction. The issue here is that sulfuric acid first displaces HI from an iodide, but it then oxidises it to iodine and in turn gets reduced to sulfur(IV oxide and even hydrogen sulfide.
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#4
(Original post by Jshek)
How do i answer 5. So what is the charge on the product side because you said Mg is 0
How do i answer 5. So what is the charge on the product side because you said Mg is 0
Group 2 elements form 2+ ions
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