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im stuck on this maths thing

so, basically how on earth does
cos(x+20) turn into sin(90-20-x)

if u want the full question,


given that 4sin(x+70) = cos(x+20) show that tanx = -3/5tan(70)
Generally for any angle xx in degrees, cos(90x)=sinx\cos(90-x)=\sin x; and equivalently cosx=sin(90x)\cos x = \sin(90-x).

When 0<x<900<x<90, we can see this using a right-angled triangle—but it infact holds more generally for any value of xx in degrees.

(When xx is in radians, we put π2\frac{\pi}{2} instead of 9090.)
(edited 3 years ago)
Reply 2
Original post by Integer123
Generally for any angle xx in degrees, cos(90x)=sinx\cos(90-x)=\sin x; and equivalently cosx=sin(90x)\cos x = \sin(90-x).

When 0<x<900<x<90, we can see this using a right-angled triangle—but it infact holds more generally for any value of xx in degrees.

(When xx is in radians, we put π2\frac{\pi}{2} instead of 9090.)

okat thank you. :smile:

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