complex coefficients

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#1
What can you say about what the roots of cubic with complex coefficients will be ?
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1 week ago
#2
(Original post by LElizabeth02)
What can you say about what the roots of cubic with complex coefficients will be ?
They will not necessarily occur in conjugate pairs.
Last edited by RDKGames; 1 week ago
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1 week ago
#3
(Original post by RDKGames)
They will not occur in conjugate pairs.
Some of this is going to be a bit pedantic, but I think this question is actually a bit of a minefield.

Firstly, , so arguably is still a poly with complex coefficients.

But even if we exclude this bit of pedantry, obviously is a poly with complex coefficients.

To get around that, let's insist that our poly is monic. Then what about . At a minimum, this has (a pair of) roots that come in conjugate pairs; arguably, *all* of its roots come in conjugate pairs (if you say that the only *roots* are x = i, x = -i).

It's probably one of those questions where you really need to ask the OP why they're asking.
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1 week ago
#4
(Original post by DFranklin)
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