# Is my answer correct?

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The graph is below but my answer is

Yes, Lines A and B are perpendicular this is because they both intercept causing a right angle and they are opposite reciprocals of each other

Yes, Lines A and B are perpendicular this is because they both intercept causing a right angle and they are opposite reciprocals of each other

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#3

Did you calculate the gradient of each line?

Last edited by medicalsupernova; 3 days ago

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#4

(Original post by

The graph is below but my answer is

Yes, Lines A and B are perpendicular this is because they both intercept causing a right angle and they are opposite reciprocals of each other

**Kakakaty**)The graph is below but my answer is

Yes, Lines A and B are perpendicular this is because they both intercept causing a right angle and they are opposite reciprocals of each other

**gradients**.

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(Original post by

Did you calculate the gradient of each line?

**medicalsupernova**)Did you calculate the gradient of each line?

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#7

(Original post by

Oh no I didnt, I just did and I get different answers does that mean they're not?

**Kakakaty**)Oh no I didnt, I just did and I get different answers does that mean they're not?

What do you know about the gradients of perpendicular lines?

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(Original post by

What are your values for the gradients of each line?

What do you know about the gradients of perpendicular lines?

**davros**)What are your values for the gradients of each line?

What do you know about the gradients of perpendicular lines?

I know that their gradients will multiply together to give -1 but from the gradient I got they don't equal -1 so does that mean theyre not perpendicular or did i do my calculations wrong?

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#9

**Kakakaty**)

Oh no I didnt, I just did and I get different answers does that mean they're not?

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#10

(Original post by

their gradients need to be negative

**mnot**)their gradients need to be negative

**recipricles**of each other to be perpendicular.**reciprocals**for anyone trying to google this

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#11

(Original post by

Anyone know?

**Kakakaty**)Anyone know?

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(Original post by

hint: the Tan theta1 and Tan theta 2 has a relationship for perpendicular lines

**Melvin Guna**)hint: the Tan theta1 and Tan theta 2 has a relationship for perpendicular lines

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#13

(Original post by

I'm not too sure what this means, could you explain some more?

**Kakakaty**)I'm not too sure what this means, could you explain some more?

Last edited by Melvin Guna; 3 days ago

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#14

(Original post by

for A i got 3 and for B i got 2.5

I know that their gradients will multiply together to give -1 but from the gradient I got they don't equal -1 so does that mean theyre not perpendicular or did i do my calculations wrong?

**Kakakaty**)for A i got 3 and for B i got 2.5

I know that their gradients will multiply together to give -1 but from the gradient I got they don't equal -1 so does that mean theyre not perpendicular or did i do my calculations wrong?

Also the gradient of line A is < 1.

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(Original post by

You must realise line B has a negative gradient as it goes down.

Also the gradient of line A is < 1.

**mqb2766**)You must realise line B has a negative gradient as it goes down.

Also the gradient of line A is < 1.

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#16

Hello! For each line, work out the equation of the line in the form y = mx + c, where m is your gradient, c is your y intercept.

For A: You can see in the graph your y intercept is 4. Pick a point on the line that is clear i.e (6,6) and sub these numbers in for y and x. Rearrange to calculate m(a).

For B: Your Y intercept is 10. Do the same for a point that lies on B. (2,5) for example. Rearrange to calculate m(b)

Does m(a) x m(b) = -1?

If yes, they are perpendicular

If no, they're not

For A: You can see in the graph your y intercept is 4. Pick a point on the line that is clear i.e (6,6) and sub these numbers in for y and x. Rearrange to calculate m(a).

For B: Your Y intercept is 10. Do the same for a point that lies on B. (2,5) for example. Rearrange to calculate m(b)

Does m(a) x m(b) = -1?

If yes, they are perpendicular

If no, they're not

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#17

(Original post by

Hello! For each line, work out the equation of the line in the form y = mx + c, where m is your gradient, c is your y intercept.

For A: You can see in the graph your y intercept is 4. Pick a point on the line that is clear i.e (6,6) and sub these numbers in for y and x. Rearrange to calculate m(a).

For B: Your Y intercept is 10. Do the same for a point that lies on B. (2,5) for example. Rearrange to calculate m(b)

Does m(a) x m(b) = -1?

If yes, they are perpendicular

If no, they're not

**Always_Confused**)Hello! For each line, work out the equation of the line in the form y = mx + c, where m is your gradient, c is your y intercept.

For A: You can see in the graph your y intercept is 4. Pick a point on the line that is clear i.e (6,6) and sub these numbers in for y and x. Rearrange to calculate m(a).

For B: Your Y intercept is 10. Do the same for a point that lies on B. (2,5) for example. Rearrange to calculate m(b)

Does m(a) x m(b) = -1?

If yes, they are perpendicular

If no, they're not

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