Original post by macy_m
Okay so I’ve checked it and I believe you can, first thing expand the brackets and sum everything up 
then tell me what you got and I’ll check
then tell me what you got and I’ll checkI got 3n²+6n+5 after expanding it all and adding them
Original post by Mystxgon
I got 3n² 6n 5 after expanding it all and adding them
So then you’d factorise the 3 our and be left with a 5 outside but that wouldn’t work so you’d have to have a -1 outside, do you know how you could word it then?
(edited 3 years ago)
So, what do you get if you add 1? Can you see why it's a multiple of 3?
Incidentally, you could also consider your 3 consecutive squares to be (n-1)^2, n^2, (n+1)^2, in which case symmetry is going to make your calculations slightly easier. No big deal here, but something to be aware of for harder problems.
Incidentally, you could also consider your 3 consecutive squares to be (n-1)^2, n^2, (n+1)^2, in which case symmetry is going to make your calculations slightly easier. No big deal here, but something to be aware of for harder problems.
(edited 3 years ago)
Original post by macy_m
So then you’d factorise the 3 our and be left with a +5 outside, do you know how you could word it then?
Thank u for the help i understand it now 3(n²+2n+2) -1 i believe?
Original post by Mystxgon
Thank u for the help i understand it now 3(n²+2n+2) -1 i believe?
Yes !
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