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loga x^2 + ln x^3 + 6 loga x

for ln a = 3.

how do i simply this expression?

If you know how to do can you please explain it step by step

for ln a = 3.

how do i simply this expression?

If you know how to do can you please explain it step by step

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#2

(Original post by

loga x^2 + ln x^3 + 6 loga x

for ln a = 3.

how do i simply this expression?

If you know how to do can you please explain it step by step

**Selekt1234**)loga x^2 + ln x^3 + 6 loga x

for ln a = 3.

how do i simply this expression?

If you know how to do can you please explain it step by step

Some common log rules at

https://www.mathsisfun.com/algebra/e...ogarithms.html

Have a think about which may be useful?

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i have done it which simplified to 17/3lnx

can anyone let me know if its wrong or right?

and part 2 of the question is loga x^2 + ln x^3 + 6 loga x=17/3lnx

but it doesnt quite make sense to me as there is no solution to it with my answer (ps logax does mean log base a)

Also i have another question which is a simoultaneous equations which is

lnx+2lny=ln3

lnx+lny=1

i have done it and i got

x=3e^2

y=0.1222

can you let me know if its correct becaseu when i plug them back in the equation i get 0,997 and i dont get 1 exactly

can anyone let me know if its wrong or right?

and part 2 of the question is loga x^2 + ln x^3 + 6 loga x=17/3lnx

but it doesnt quite make sense to me as there is no solution to it with my answer (ps logax does mean log base a)

Also i have another question which is a simoultaneous equations which is

lnx+2lny=ln3

lnx+lny=1

i have done it and i got

x=3e^2

y=0.1222

can you let me know if its correct becaseu when i plug them back in the equation i get 0,997 and i dont get 1 exactly

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#4

(Original post by

i have done it which simplified to 17/3lnx

can anyone let me know if its wrong or right?

and part 2 of the question is loga x^2 + ln x^3 + 6 loga x=17/3lnx

but it doesnt quite make sense to me as there is no solution to it with my answer (ps logax does mean log base a)

Also i have another question which is a simoultaneous equations which is

lnx+2lny=ln3

lnx+lny=1

i have done it and i got

x=3e^2

y=0.1222

can you let me know if its correct becaseu when i plug them back in the equation i get 0,997 and i dont get 1 exactly

**Selekt1234**)i have done it which simplified to 17/3lnx

can anyone let me know if its wrong or right?

and part 2 of the question is loga x^2 + ln x^3 + 6 loga x=17/3lnx

but it doesnt quite make sense to me as there is no solution to it with my answer (ps logax does mean log base a)

Also i have another question which is a simoultaneous equations which is

lnx+2lny=ln3

lnx+lny=1

i have done it and i got

x=3e^2

y=0.1222

can you let me know if its correct becaseu when i plug them back in the equation i get 0,997 and i dont get 1 exactly

Last edited by mqb2766; 4 weeks ago

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#5

(Original post by

how do i simply this expression?

If you know how to do can you please explain it step by step

**Selekt1234**)how do i simply this expression?

If you know how to do can you please explain it step by step

for ln a = 3

ln(a.x^2)/ln10 +ln(x^3) + ln(a.x)/ln10 {assuming log is to base 1}

then you get:

(Ln a +lnx^2)/ln10 +(lna+ ln x)/ln10 + lnx^3

3/ln10 +2lnx/ln10 +3/ln10 + lnx/ln10 +3lnx

6/ln10+3lnx/ln10 +3lnx

(6+3lnx)/ln10 +3lnx

(6x^3 +(3x^3)lnx)/ln10

might be wrong. Too sleepy atm!

Last edited by boulderingislife; 4 weeks ago

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#6

**Selekt1234**)

i have done it which simplified to 17/3lnx

can anyone let me know if its wrong or right?

and part 2 of the question is loga x^2 + ln x^3 + 6 loga x=17/3lnx

but it doesnt quite make sense to me as there is no solution to it with my answer (ps logax does mean log base a)

Also i have another question which is a simoultaneous equations which is

lnx+2lny=ln3

lnx+lny=1

i have done it and i got

x=3e^2

y=0.1222

can you let me know if its correct becaseu when i plug them back in the equation i get 0,997 and i dont get 1 exactly

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is x not 3e^2

if not what is it

and according to you y would be y=e^1-ln(3e^2)

and also regarding 17/3lnx

my working out

ln(a)=3

so converted everything into Ln using change of base formula

and got 1/3lnx^2+lnx^3+lnx^2 and then turned them into all lnx

2/3lnx+3lnx+2lnx=17/3lnx

if not what is it

and according to you y would be y=e^1-ln(3e^2)

and also regarding 17/3lnx

my working out

ln(a)=3

so converted everything into Ln using change of base formula

and got 1/3lnx^2+lnx^3+lnx^2 and then turned them into all lnx

2/3lnx+3lnx+2lnx=17/3lnx

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#8

17/3 ln(x) looks good to me.

Can you upload a pic of the original question?

Can you upload a pic of the original question?

Last edited by mqb2766; 4 weeks ago

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#9

(Original post by

is x not 3e^2

if not what is it

and according to you y would be y=e^1-ln(3e^2)

**Selekt1234**)is x not 3e^2

if not what is it

and according to you y would be y=e^1-ln(3e^2)

Take a step back and work from the basics.

You have lnx + 2lny = ln3 which means using one of the log rules, or applying another log rule. So what can you say about ?

Now trying following the same principle with the second equation and see what you can deduce about xy.

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#11

Does it satisfy the 1st equation: lnx + 2lny = ln3 ?

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#13

and

then I think those are technically correct, however, you haven't simplified them as much as you can!

How can you write those answers in simplified form?

(Hint: there shouldn't be any logarithms left in the final answer.)

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Also I have another question

Simplify

log3x+log9x

3 and 9=base

So I changed the base to 3

I got log3(x)/log3(9) which equals to 1/2log3(x) right then if I take the power up it will be log3(x^1/2)

So then it’s multiplication of log3(x X x^1/2) which =log3x^3\2

But when I keep the 1/2 and not put it as a power 1/2logx^2 so which would be the right answer

Simplify

log3x+log9x

3 and 9=base

So I changed the base to 3

I got log3(x)/log3(9) which equals to 1/2log3(x) right then if I take the power up it will be log3(x^1/2)

So then it’s multiplication of log3(x X x^1/2) which =log3x^3\2

But when I keep the 1/2 and not put it as a power 1/2logx^2 so which would be the right answer

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#15

(Original post by

Also I have another question

Simplify

log3x+log9x

3 and 9=base

So I changed the base to 3

I got log3(x)/log3(9) which equals to 1/2log3(x) right then if I take the power up it will be log3(x^1/2)

So then it’s multiplication of log3(x X x^1/2) which =log3x^3\2

But when I keep the 1/2 and not put it as a power 1/2logx^2 so which would be the right answer

**Selekt1234**)Also I have another question

Simplify

log3x+log9x

3 and 9=base

So I changed the base to 3

I got log3(x)/log3(9) which equals to 1/2log3(x) right then if I take the power up it will be log3(x^1/2)

So then it’s multiplication of log3(x X x^1/2) which =log3x^3\2

But when I keep the 1/2 and not put it as a power 1/2logx^2 so which would be the right answer

If

then you end up with

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(Original post by

You seem to have forgotten to add the other term when you converted to

If

then you end up with

**davros**)You seem to have forgotten to add the other term when you converted to

If

then you end up with

Last edited by Selekt1234; 4 weeks ago

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#17

(Original post by

initially I got what you got but however I put it on Photomath it gives me 1/2logx^2

**Selekt1234**)initially I got what you got but however I put it on Photomath it gives me 1/2logx^2

Anyway, working out the algebra according to the log rules is the safe way to go

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