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maths question

the region r is bounded by the x axis and the curve with the equation y=x^2(k-x ) and area r is 108 find value of k
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y=kx^2-x^3
Use this to find the value of k by integration.
Original post by bejie
the region r is bounded by the x axis and the curve with the equation y=x^2(k-x ) and area r is 108 find value of k

y=kx^2-x^3

Integral of y between y = k and 0 is:
Kx^3/3-x^4/4 between k and 0 = 108
K^4/3-k^4/4 =108
K^4/12=108
K^4=1296
K=6

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