# Numerical solutions of eq

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#2

(Original post by

I dont understand how to do question 9(a)

**Shas72**)I dont understand how to do question 9(a)

Its a relatively simple area question with a bit of working required on the radius of the sector?

If you work back from the answer, can you spot any structure?

Last edited by mqb2766; 1 month ago

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(Original post by

What do you understand?

Its a relatively simple area question with a bit of working required on the radius of the sector?

If you work back from the answer, can you spot any structure?

**mqb2766**)What do you understand?

Its a relatively simple area question with a bit of working required on the radius of the sector?

If you work back from the answer, can you spot any structure?

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#4

(Original post by

Is it that i have to calculate the area of triangle ABC?

**Shas72**)Is it that i have to calculate the area of triangle ABC?

Try and write down some equations and upload when you get stuck.

Did you try working backwards?

Last edited by mqb2766; 1 month ago

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(Original post by

You could do but you'd have to do the additional segment as well. Isn't the sector easier?

Try and write down some equations and upload when you get stuck.

Did you try working backwards?

**mqb2766**)You could do but you'd have to do the additional segment as well. Isn't the sector easier?

Try and write down some equations and upload when you get stuck.

Did you try working backwards?

Area of shaded region = 3/8× area of circle

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**mqb2766**)

You could do but you'd have to do the additional segment as well. Isn't the sector easier?

Try and write down some equations and upload when you get stuck.

Did you try working backwards?

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#7

(Original post by

So I did area of shaded region= area of circle - area of sector abc.

Area of shaded region = 3/8× area of circle

**Shas72**)So I did area of shaded region= area of circle - area of sector abc.

Area of shaded region = 3/8× area of circle

What variables, formulae, ..

Did you try working backwards...

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(Original post by

isn't the shaded region the sector?

What variables, formulae, ..

Did you try working backwards...

**mqb2766**)isn't the shaded region the sector?

What variables, formulae, ..

Did you try working backwards...

(Original post by

That radius is not r

**mqb2766**)That radius is not r

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(Original post by

That radius is not r

**mqb2766**)That radius is not r

**mqb2766**)

isn't the shaded region the sector?

What variables, formulae, ..

Did you try working backwards...

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#11

* Step away from the reply button for a time and draw/think about the problem

* Work back from the answer, can you get an "area = 3/8 area" type expression. Does that give you any hints?

* Draw 0A and/or OB on your diagram. How does that help you relate the radii.

Upload your thoughts/working after a bit of thinking. There is nothing beyond a hard gcse question here. Working backwards from the desired expression can, in some cases, give you hints about how the analysis is done.

Last edited by mqb2766; 1 month ago

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(Original post by

A couple of things

* Step away from the reply button for a time and draw/think about the problem

* Work back from the answer, can you get an "area = 3/8 area" type expression. Does that give you any hints?

* Draw 0A and/or OB on your diagram. How does that help you relate the radii.

Upload your thoughts/working after a bit of thinking. There is nothing beyond a hard gcse question here. Working backwards from the desired expression can, in some cases, give you hints about how the analysis is done.

**mqb2766**)A couple of things

* Step away from the reply button for a time and draw/think about the problem

* Work back from the answer, can you get an "area = 3/8 area" type expression. Does that give you any hints?

* Draw 0A and/or OB on your diagram. How does that help you relate the radii.

Upload your thoughts/working after a bit of thinking. There is nothing beyond a hard gcse question here. Working backwards from the desired expression can, in some cases, give you hints about how the analysis is done.

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reply

**mqb2766**)

A couple of things

* Step away from the reply button for a time and draw/think about the problem

* Work back from the answer, can you get an "area = 3/8 area" type expression. Does that give you any hints?

* Draw 0A and/or OB on your diagram. How does that help you relate the radii.

Upload your thoughts/working after a bit of thinking. There is nothing beyond a hard gcse question here. Working backwards from the desired expression can, in some cases, give you hints about how the analysis is done.

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#14

(Original post by

Iam not understanding how to approach this question. Can you pls explain in a simpler way if possible?

**Shas72**)Iam not understanding how to approach this question. Can you pls explain in a simpler way if possible?

Please give me something to work with.

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#15

**Shas72**)

Iam not understanding how to approach this question. Can you pls explain in a simpler way if possible?

So what you really need to do at this point is find out what R is. This

**is**basically GCSE geometry, but it seems to be something a lot of A-level students struggle with.

You know two sides of the triangle AOC = r. So, that triangle is isoceles. Does that help?

Spoiler:

Show

If AOC is isoceles, then if you set M to be the midpoint of AC, drawing the line OM divides the triangle into 2 smaller right angled triangles. From there it's easy to find AM (or CM).

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(Original post by

What picture have you drawn? What equations are you using for the area of the circle / sector. Working backwards steps would be appreciated. Can you p!s upload what you've done.

Please give me something to work wit

**mqb2766**)What picture have you drawn? What equations are you using for the area of the circle / sector. Working backwards steps would be appreciated. Can you p!s upload what you've done.

Please give me something to work wit

(Original post by

So, I assume you're happy that if we knew the radius R of the sector, then the area of the shaded region would be R^2 theta?

So what you really need to do at this point is find out what R is. This

You know two sides of the triangle AOC = r. So, that triangle is isoceles. Does that help?

**DFranklin**)So, I assume you're happy that if we knew the radius R of the sector, then the area of the shaded region would be R^2 theta?

So what you really need to do at this point is find out what R is. This

**is**basically GCSE geometry, but it seems to be something a lot of A-level students struggle with.You know two sides of the triangle AOC = r. So, that triangle is isoceles. Does that help?

Spoiler:

Show

If AOC is isoceles, then if you set M to be the midpoint of AC, drawing the line OM divides the triangle into 2 smaller right angled triangles. From there it's easy to find AM (or CM).

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(Original post by

Why (and no)?

**mqb2766**)Why (and no)?

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#19

(Original post by

Since oc is perpendicular to oa and ob

**Shas72**)Since oc is perpendicular to oa and ob

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(Original post by

Where does it say that in the question?

**mqb2766**)Where does it say that in the question?

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