thisQUEENslayz
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May I please have some assistance with questions 8,10 and 5(the last one)

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RogerOxon
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(Original post by thisQUEENslayz)
May I please have some assistance with questions 8,10 and 5(the last one)
(xy)^a=x^a \times y^a

x^a x^b=x^{a+b}

\frac{1}{x^a}=x^{-a}

(x^a)^b=x^{ab}

Use these to attempt the questions. I'll start a couple for you in my next post.
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RogerOxon
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9a^{-2} \times \frac{1}{3}a^{-3} \div \frac{2}{3}a^{-2} = \frac{\frac{9}{3}a^{-2} \times a^{-3}}{\frac{2}{3}a^{-2}}=\frac{9a^{-5}}{2a^{-2}}=\frac{9}{2}a^{-5} \times a^2=..
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RogerOxon
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(6b^{\frac{-1}{3}})^{-2} \div 6b:

Let's start with (6b^{\frac{-1}{3}})^{-2}:

(6b^{\frac{-1}{3}})^{-2} = 6^{-2} \times (b^\frac{-1}{3})^{-2}=\frac{1}{6^2} \times b^{\frac{2}{3}} = ..
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thisQUEENslayz
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(Original post by RogerOxon)
(6b^{\frac{-1}{3}})^{-2} \div 6b:

Let's start with (6b^{\frac{-1}{3}})^{-2}:

(6b^{\frac{-1}{3}})^{-2} = 6^{-2} \times (b^\frac{-1}{3})^{-2}=\frac{1}{6^2} \times b^{\frac{2}{3}} = ..
Thank you very much for this I’ll try these and get back to you
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