# help with very tricky expanding and factorising questions

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#21
(Original post by mqb2766)
b = 2(p+1)
c = 3

Not sure of your background, but I'd recommend going over something like
https://www.bbc.co.uk/bitesize/guide...d2p/revision/1
Before going any further. That has the very basics, try doing the simple exercises first.
ahhh i think i get it now
a = 7(p + 1)
b = 2(p + 1)
c= 3

then we substitute into the formula

7(p+1) * b + 7(p+1) * c = 7(p+1)(b+c)

7(p+1)* 2(p+1) + 7(p+1) * 3 = 7(p+1)*2(p+1) + 3

then we expand 2(p+1) which is 2p+2

and then we add 3 to that which is 2p+5

7(p+1)(2p+5)
0
2 months ago
#22
(Original post by kyefrankie)
ahhh i think i get it now
a = 7(p + 1)
b = 2(p + 1)
c= 3

then we substitute into the formula

7(p+1) * b + 7(p+1) * c = 7(p+1)(b+c)

7(p+1)* 2(p+1) + 7(p+1) * 3 = 7(p+1)*2(p+1) + 3

then we expand 2(p+1) which is 2p+2

and then we add 3 to that which is 2p+5

7(p+1)(2p+5)
Sure, make sure you put all the brackets in the working steps.
The other ones are similar. Have a go and think
* what are factors for each term
* Which factors are common
* How to combine what's left
Have a good think about them and check each step yourself before asking for help. It's the best way to learn, but post if you get really stuck.
0
#23
(Original post by mqb2766)
Sure, make sure you put all the brackets in the working steps.
The other ones are similar. Have a go and think
* what are factors for each term
* Which factors are common
* How to combine what's left
Have a good think about them and check each step yourself before asking for help. It's the best way to learn, but post if you get really stuck.
thank you very much for your time and stay safe
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