!AXEL!
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if delta G = 0 does that mean the reaction is feasible or not feasible?
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in.cendium
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From the AQA specification - "For a reaction to be feasible, the value of ∆G must be zero or negative."
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!AXEL!
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(Original post by in.cendium)
From the AQA specification - "For a reaction to be feasible, the value of ∆G must be zero or negative."
is it the same for ocr?
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Pigster
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(Original post by !AXEL!)
is it the same for ocr?
It is the same for everyone as that is what is correct.

Oddly, all exam boards teach the same stuff. If Mg is more reactive than Fe in AQA, then it is also more reactive in OCR. That'll be because it is more reactive. The exam boards aren't just making all this up.
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!AXEL!
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(Original post by in.cendium)
From the AQA specification - "For a reaction to be feasible, the value of ∆G must be zero or negative."
is it the same definition for ocr?
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in.cendium
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(Original post by !AXEL!)
is it the same definition for ocr?
yes !
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!AXEL!
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(Original post by in.cendium)
yes !
thanks my computer was slow so it didnt load it when i first asked the question
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