Shas72
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its the 8th question (ii)
I dont understand what should be the starting valueName:  16010394067295483451208756162154.jpg
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mqb2766
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It (2a) is the "width" of the given integral. Looking at the average integrand, I'd try a starting value of about 1 or 2.
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Shas72
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(Original post by mqb2766)
It (2a) is the "width" of the given integral. Looking at the average integrand, I'd try a starting value of about 1 or 2.
So if the starting value isn't given should I just take value between 1 and 2
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mqb2766
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(Original post by Shas72)
So if the starting value isn't given should I just take value between 1 and 2
That range is based on what the function represents. In this case:
* Sketch the integrand from -3 to 3 say
* What interval [-a,a] would the area under the curve be approximately 100?,

Alternatively, guesstimate a value from the iteration formula. ln() must be positive, so a cannot be too large.

You can't just assume it's 1 or 2 for an arbitrary function.
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Shas72
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(Original post by mqb2766)
It (2a) is the "width" of the given integral. Looking at the average integrand, I'd try a starting value of about 1 or 2.
Thank you very much
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