Hi, can someone explain why, in part b, when taking things to their respective sides, in order to integrate them, the markscheme takes 20 to the P side - basically forming 20/(P(5-2P)). I find this really confusing as in part A it asks u to find partial fractions of 1/ P(5-2P) , and in literally every question I’ve seen where it asks u to do something beforehand, u always use that to ur advantage in the next part of the question, so I only bought the P(5-2P) to the other side, and left the right hand side as 1/20, but got the answer wrong.
Do you mind explaining to me where I’ve gone wrong ? I’ve subbed in the right things and I’m fairly certain my maths it right (?) but I’m getting a negative number for weeks. Markscheme started off with taking 20 to the other side as well, but I wanna try getting to the answer by leaving 20 on the RHS, as that is what I’d probably do in the exam. Thanks.