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how to show a function is invertible

    • Thread Starter

    say f(x)=(4x^3)/((x^2) + 1)

    how can i show f has an inverse?

    i understand that for a function to be invertible, f(x1) does not equal f(x2) whenever x1 does not equal x2. but im unsure how i can apply it to the above function. help please, thanks

    Well, there are many ways to prove that a function is injective and hence has the inverse you seek. One of them is to show that the function is increasing (Can you see why)
    • Thread Starter

    no not really...

    If the function is strictly increasing then f(x_2) > f(x_1) whenever x_2 > x_1. You should be able to see that this implies the function is also injective.
    • Thread Starter

    (Original post by Kolya)
    If the function is strictly increasing then f(x_2) > f(x_1) whenever x_2 > x_1. So, clearly, f(x_1) cannot equal f(x_2) whenever x_1 \neq x_2. Hence strictly increasing means the function is injective.
    oh i get it now, but is that enough proof? would i need to give some values or something?
    • Thread Starter

    ignore that, thanks

    Within the context of the question, I think it would be enough to just state that strictly increasing implies injective, and then use that idea to complete the question. (However, the proof of the intermediate result is easy.)
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