(Original post by lucaz)
What mass of Aluminium metal will react exactly with 25cm^3 of 0.012 M sulphuric acid? (RAM: Al = 27). Use the equation
2Al(s) + 6H+ (aq) ----> 2Al3+ (aq) + 3H2(g)
you don't have suphuric acid in there as far as I can see. use naming rules to set up the equation...balance it. and then use stoic.
Al has a charge of 3 so it would be
2Al+3(H2SO4) -> Al2(SO4)3 + 3H2
and then set up a fencepost
25cm^3 H2SO4 X 1 mL H2SO4 X .001L H2SO4 X .012m H2SO4
1cm^3H2SO4_____1mL H2SO4______1L H2SO4
that gives you how many moles you have of sulfuric acid (.0003m H2SO4)
and THEN you do a simple mole to mole ratio
(first find how many grams per mole there is in sulfuric acid) 98.078g
and then the second equation.......
.0003mH2SO4 X 3mAl X 26.982gAl
should equal about .0121gAl.....
but that seems rather small.