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file:///C:/Users/Nagas/Desktop/electrode%20potential%20question %20.pdf
the above file is the link to my question, i need help on understanding question 1 please
the above file is the link to my question, i need help on understanding question 1 please
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#2
Oops, your link is to a document on your Windows PC, not an Internet shared link,
In general all electrode potential questions go back to Michael Faraday
Try https://www.cliffsnotes.com/study-gu...rode-potential
In general all electrode potential questions go back to Michael Faraday
Try https://www.cliffsnotes.com/study-gu...rode-potential
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(Original post by LuigiMario)
Oops, your link is to a document on your Windows PC, not an Internet shared link,
In general all electrode potential questions go back to Michael Faraday
Try https://www.cliffsnotes.com/study-gu...rode-potential
Oops, your link is to a document on your Windows PC, not an Internet shared link,
In general all electrode potential questions go back to Michael Faraday
Try https://www.cliffsnotes.com/study-gu...rode-potential
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i am confused with question 1, can you please explain it to me so i can make notes on it
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(Original post by !AXEL!)
i am confused with question 1, can you please explain it to me so i can make notes on it
i am confused with question 1, can you please explain it to me so i can make notes on it
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#6
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#7
The calculation of electrode potential is:
dV = V1 - V2. With V1 = E°(cathode) and V2 = E°(anode), so it is dV = E°(cathode) - E°(anode)
Note: in an galvanic cell, the cathode is the reducing electrode and the anode the oxidising electrode. If you can determine the electrodes of your cell, the calculation is a piece of cake.
dV = V1 - V2. With V1 = E°(cathode) and V2 = E°(anode), so it is dV = E°(cathode) - E°(anode)
Note: in an galvanic cell, the cathode is the reducing electrode and the anode the oxidising electrode. If you can determine the electrodes of your cell, the calculation is a piece of cake.
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#8
(Original post by charco)
There is insufficient information. You need more data to be able to calculate the value of the electrode potentials.
There is insufficient information. You need more data to be able to calculate the value of the electrode potentials.
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#9
(Original post by Kallisto)
As far as I understand the text above, the potentials should be calculated with the named materials (Fe, Zn and Mg) in combination with copper respectively, or am I wrong?
As far as I understand the text above, the potentials should be calculated with the named materials (Fe, Zn and Mg) in combination with copper respectively, or am I wrong?
A half-cell is just the metal in a solution of its ions (or similar).
Each of the values given is for the metal half-cell standard reduction potential.
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