localmemelord
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#1
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#1
vector product definition: which is correct and why?
a x b =|a||b|sin(theta)

or

a x b =|a||b|sin(theta) n^

why is the n^ there in some of the definitions
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DFranklin
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#2
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Vector product is a vector (it's in the name ). So 2nd definition is correct as it defines a vector.

The first definition is clearly wrong. Where on earth have you seen that?
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RDKGames
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#3
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(Original post by DFranklin)
Vector product is a vector (it's in the name ). So 2nd definition is correct as it defines a vector.

The first definition is clearly wrong. Where on earth have you seen that?
Probably seen the magnitude of axb written as that, hence confusion
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localmemelord
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#4
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(Original post by DFranklin)
Vector product is a vector (it's in the name ). So 2nd definition is correct as it defines a vector.

The first definition is clearly wrong. Where on earth have you seen that?
can you pls explain why theres an n^ in the correct definition cause shouldnt it be a x b =|a||b|sin(theta) = n^
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DFranklin
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(Original post by localmemelord)
can you pls explain why theres an n^ in the correct definition cause shouldnt it be a x b =|a||b|sin(theta) = n^
Because the vector product defines a vector perpendicular to both a and b.
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localmemelord
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#6
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(Original post by DFranklin)
Because the vector product defines a vector perpendicular to both a and b.
no i understand that thanks. but i dont understand why the unit vector is within the equation because ive seen questions where they dont incorperate n^ when calculating a x b for example
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DFranklin
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(Original post by localmemelord)
no i understand that thanks. but i dont understand why the unit vector is within the equation because ive seen questions where they dont incorperate n^ when calculating a x b for example
If you have, the question is wrong. (Although it's far more likely you're missing something out, such as they actually calculated |a x b|).
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localmemelord
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#8
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(Original post by DFranklin)
If you have, the question is wrong. (Although it's far more likely you're missing something out, such as they actually calculated |a x b|).
im still confused as to what n^ or n in comparison to vectors a and b
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DFranklin
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(Original post by localmemelord)
im still confused as to what n^ or n in comparison to vectors a and b
n is a unit vector perpendicular to both a and b.
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localmemelord
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#10
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(Original post by DFranklin)
n is a unit vector perpendicular to both a and b.
ok so if a x b = c and c is the vector perpendicular to a and b then does that mean that vector n in n^ = n/|n| equal to vector c
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RDKGames
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(Original post by localmemelord)
ok so if a x b = c and c is the vector perpendicular to a and b then does that mean that vector n in n^ = n/|n| equal to vector c
He meant that n^ is the unit vector. Thats what the 'hat' on top of n means.

If a x b = c, then n=c and n^ = c/|c|
Last edited by RDKGames; 7 months ago
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localmemelord
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#12
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(Original post by RDKGames)
He meant that n^ is the unit vector. Thats what the 'hat' on top of n means.

If a x b = c, then n=c and n^ = c/|c|
great i understand now thanks guys DFranklin RDKGames
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