# Urgent Maths help!!

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Hi I really really need help, I've got this maths homework due tomorrow and I'm not sure what to do on a few and if I've even done a few right could someone please please have a look! Thank you!!

I can't attach images so I'll type it out:

1) Factorise each quadratic

a)5x^2 + 5x - 10

My answer: I divided by 5, x^2 + x - 2 answer = (x+2)(x-1)

b)15x^2 - 72x - 15

My answer: Divided by 3, 5x^2 - 24 - 5 = (-5+x)(5x-1)

Solve: 3 * 4^(2k+8) = 24

IDK WHAT TO DO!

Factorise fully (w+4)^3 - (w+4)^2(w+1)

HELP! This one I expanded until I eventually got 3w^2 +16w +48 but it doesn't facatorise and I'm gonna cry because someone I know got: 3(w+4)^2 and I don't understand!

Last question:

y = 16 * 10^(8k) where k is an integer

find an expression, in terms of k, for y^(5/4)

Give answer in standard form

I can't attach images so I'll type it out:

1) Factorise each quadratic

a)5x^2 + 5x - 10

My answer: I divided by 5, x^2 + x - 2 answer = (x+2)(x-1)

b)15x^2 - 72x - 15

My answer: Divided by 3, 5x^2 - 24 - 5 = (-5+x)(5x-1)

Solve: 3 * 4^(2k+8) = 24

IDK WHAT TO DO!

Factorise fully (w+4)^3 - (w+4)^2(w+1)

HELP! This one I expanded until I eventually got 3w^2 +16w +48 but it doesn't facatorise and I'm gonna cry because someone I know got: 3(w+4)^2 and I don't understand!

Last question:

y = 16 * 10^(8k) where k is an integer

find an expression, in terms of k, for y^(5/4)

Give answer in standard form

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#2

(Original post by

Hi I really really need help, I've got this maths homework due tomorrow and I'm not sure what to do on a few and if I've even done a few right could someone please please have a look! Thank you!!

I can't attach images so I'll type it out:

1) Factorise each quadratic

a)5x^2 + 5x - 10

My answer: I divided by 5, x^2 + x - 2 answer = (x+2)(x-1)

b)15x^2 - 72x - 15

My answer: Divided by 3, 5x^2 - 24 - 5 = (-5+x)(5x-1)

Solve: 3 * 4^(2k+8) = 24

IDK WHAT TO DO!

Factorise fully (w+4)^3 - (w+4)^2(w+1)

HELP! This one I expanded until I eventually got 3w^2 +16w +48 but it doesn't facatorise and I'm gonna cry because someone I know got: 3(w+4)^2 and I don't understand!

Last question:

y = 16 * 10^(8k) where k is an integer

find an expression, in terms of k, for y^(5/4)

Give answer in standard form

**FloryK**)Hi I really really need help, I've got this maths homework due tomorrow and I'm not sure what to do on a few and if I've even done a few right could someone please please have a look! Thank you!!

I can't attach images so I'll type it out:

1) Factorise each quadratic

a)5x^2 + 5x - 10

My answer: I divided by 5, x^2 + x - 2 answer = (x+2)(x-1)

b)15x^2 - 72x - 15

My answer: Divided by 3, 5x^2 - 24 - 5 = (-5+x)(5x-1)

Solve: 3 * 4^(2k+8) = 24

IDK WHAT TO DO!

Factorise fully (w+4)^3 - (w+4)^2(w+1)

HELP! This one I expanded until I eventually got 3w^2 +16w +48 but it doesn't facatorise and I'm gonna cry because someone I know got: 3(w+4)^2 and I don't understand!

Last question:

y = 16 * 10^(8k) where k is an integer

find an expression, in terms of k, for y^(5/4)

Give answer in standard form

5(x+2)(x-1)

For 3l) write 24 as a product of factors 3 and 4. What is the 4 exponent?

Last edited by mqb2766; 1 month ago

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#3

**FloryK**)

Hi I really really need help, I've got this maths homework due tomorrow and I'm not sure what to do on a few and if I've even done a few right could someone please please have a look! Thank you!!

I can't attach images so I'll type it out:

1) Factorise each quadratic

a)5x^2 + 5x - 10

My answer: I divided by 5, x^2 + x - 2 answer = (x+2)(x-1)

b)15x^2 - 72x - 15

My answer: Divided by 3, 5x^2 - 24 - 5 = (-5+x)(5x-1)

Solve: 3 * 4^(2k+8) = 24

IDK WHAT TO DO!

Factorise fully (w+4)^3 - (w+4)^2(w+1)

HELP! This one I expanded until I eventually got 3w^2 +16w +48 but it doesn't facatorise and I'm gonna cry because someone I know got: 3(w+4)^2 and I don't understand!

Last question:

y = 16 * 10^(8k) where k is an integer

find an expression, in terms of k, for y^(5/4)

Give answer in standard form

0

reply

(Original post by

You can't divide if it's an expression. Factorize. So the first one is

5(x+2)(x-1)

**mqb2766**)You can't divide if it's an expression. Factorize. So the first one is

5(x+2)(x-1)

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#5

(Original post by

Okay thank you I thought that was the case but for some reason my maths teacher wrote a hint saying "you need to divide through by a common factor first) so I was really confused as I wasn't really sure what she meant. What about the rest?

**FloryK**)Okay thank you I thought that was the case but for some reason my maths teacher wrote a hint saying "you need to divide through by a common factor first) so I was really confused as I wasn't really sure what she meant. What about the rest?

edited previous post for next one.

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(Original post by

You can't divide if it's an expression. Factorize. So the first one is

5(x+2)(x-1)

For 3l) write 24 as a product of factors 3 and 4. What is the 4 exponent?

**mqb2766**)You can't divide if it's an expression. Factorize. So the first one is

5(x+2)(x-1)

For 3l) write 24 as a product of factors 3 and 4. What is the 4 exponent?

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(Original post by

q3 divide by 3, then take log base 4

**asianism**)q3 divide by 3, then take log base 4

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#8

(Original post by

I don't understand what you mean how do I write it as a product of factors 3 and 4? 4 * 3 * 2??

**FloryK**)I don't understand what you mean how do I write it as a product of factors 3 and 4? 4 * 3 * 2??

2 = 4^?

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But then what do I do?

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#10

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(Original post by

Yes, so solve...

**mqb2766**)Yes, so solve...

So would k = -3.25 ?

How would I do the third and fourth ones?

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#14

(Original post by

Thank you so much!

So would k = -3.25 ?

How would I do the third and fourth ones?

**FloryK**)Thank you so much!

So would k = -3.25 ?

How would I do the third and fourth ones?

Generally, never expand our then attempt to factorize from scratch.

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(Original post by

For 3) there is common expression in each of the two terms? What is it, and factorize it out (don't divide).

**mqb2766**)For 3) there is common expression in each of the two terms? What is it, and factorize it out (don't divide).

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#16

(Original post by

I can see that (w+4)^2 is the common factor but how do you mean factorise it out?

**FloryK**)I can see that (w+4)^2 is the common factor but how do you mean factorise it out?

(w+4)^2 * ( a + b)

Where a and b are what remains from the original two terms.

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(Original post by

Write the two terms as

(w+4)^2 * ( a + b)

Where a and b are what remains from the original two terms.

**mqb2766**)Write the two terms as

(w+4)^2 * ( a + b)

Where a and b are what remains from the original two terms.

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#18

(Original post by

ummm so what remains from the original two terms after I'd expanded and subtracted them? so 3w^2 + 16w +48?? I don't understand

**FloryK**)ummm so what remains from the original two terms after I'd expanded and subtracted them? so 3w^2 + 16w +48?? I don't understand

a(w+4)^2 = (w+4)^3

So a = ...

For the second

b(w+4)^2 = -(w+4)^2(w+1)

So b = ...

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(Original post by

For the first term

a(w+4)^2 = (w+4)^3

So a = ...

For the second

b(w+4)^2 = -(w+4)^2(w+1)

So b = ...

**mqb2766**)For the first term

a(w+4)^2 = (w+4)^3

So a = ...

For the second

b(w+4)^2 = -(w+4)^2(w+1)

So b = ...

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#20

(Original post by

um would a = (w+4) and b = (w+1) ???????

**FloryK**)um would a = (w+4) and b = (w+1) ???????

That's what it means to factorize. Take out the common parts and combine what's left.

So what is the final answer?

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