# maths help

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#1
Find, correct to 2 decimal places, the largest solution in the given interval.
3sin(x) + tan(x) = 0 for -180<x<180

so far, I converted tan(x) into sin(x)/cos(x) but then idk what to do next?
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1 month ago
#2
(Original post by jungkook123)
Find, correct to 2 decimal places, the largest solution in the given interval.
3sin(x) + tan(x) = 0 for -180<x<180

so far, I converted tan(x) into sin(x)/cos(x) but then idk what to do next?
Factorize out sin(x)
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#3
(Original post by mqb2766)
Factorize out sin(x)
so would it be sin(x)(3 + 1/cos(x))?
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1 month ago
#4
(Original post by jungkook123)
so would it be sin(x)(3 + 1/cos(x))?
Yes, so treat each term separately and solve for x.
Last edited by mqb2766; 1 month ago
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#5
(Original post by mqb2766)
Yes, so great each term separately and solve for x.
what do you mean by great each term
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1 month ago
#6
(Original post by jungkook123)
what do you mean by great each term
You have a product of factors = 0, so one of them must be zero. Just do the usual argument.
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#7
(Original post by mqb2766)
You have a product of factors = 0, so one of them must be zero. Just do the usual argument.
sorry I don't understand what to do
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1 month ago
#8
(Original post by jungkook123)
sorry I don't understand what to do
sin(x)=0
Or
3+1/cos(x)=0
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#9
(Original post by mqb2766)
sin(x)=0
Or
3+1/cos(x)=0
so what do I do now?
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1 month ago
#10
(Original post by jungkook123)
so what do I do now?
What's stopping you solving for x?
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#11
(Original post by mqb2766)
What's stopping you solving for x?
for the 3+1/cos(x) would cos(x)=-1/3?
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1 month ago
#12
(Original post by jungkook123)
for the 3+1/cos(x) would cos(x)=-1/3?
3+1/cos(x)=0
Don't forget the =0.

Yes that is obviously correct.
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#13
(Original post by mqb2766)
3+1/cos(x)=0
Don't forget the =0.

Yes that is obviously correct.
I get it now, thank you for your help!!!
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