Rhys_M
Badges: 9
Rep:
?
#1
Report Thread starter 1 month ago
#1
Hhhhhhhhh
Last edited by Rhys_M; 1 month ago
0
reply
Prince Philip
  • Study Helper
Badges: 20
Rep:
?
#2
Report 1 month ago
#2
What have you tried? Please post your working.
0
reply
ManLike007
Badges: 19
Rep:
?
#3
Report 1 month ago
#3
(Original post by Rhys_M)
I can do the bit where you find dx but i literally have no idea what to do next
You want to use u = \sec{x}

Work out the new limits using u=\sec{x}

Differentiate both sides:
\dd{d}u = \sec{x}\tan{x}\ dx

Use this equation to substitute in for dx into du into the original integral. Dont' forget your new limits. You'll find that it nicely simplifies which can be re-expressed in terms of u. From here, it's a straight forward integral you should be able to solve.
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

Should there be a new university admissions system that ditches predicted grades?

No, I think predicted grades should still be used to make offers (665)
33.52%
Yes, I like the idea of applying to uni after I received my grades (PQA) (845)
42.59%
Yes, I like the idea of receiving offers only after I receive my grades (PQO) (385)
19.41%
I think there is a better option than the ones suggested (let us know in the thread!) (89)
4.49%

Watched Threads

View All