Madz178
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need help with this question will post the picture here
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Madz178
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here is the question
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mqb2766
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What can you work out? There are a couple of straightforward angles.
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Madz178
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(Original post by mqb2766)
What can you work out? There are a couple of straightforward angles.
so i found out the angle ABD is 52 degrees , angle bdc is 102 degrees and i thought that triangle BCD is a isosceles so i did 180-102 then divide it to get 39 i put it in the answer box and i didn't work
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(Original post by Madz178)
so i found out the angle ABD is 52 degrees , angle bdc is 102 degrees and i thought that triangle BCD is a isosceles so i did 180-102 then divide it to get 39 i put it in the answer box and i didn't work
It doesn't say that it's isosceles. Consider the large triangle, can you get ACB using the sin rule?
Then x is given by the angles in a triangle adding to 180.
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(Original post by mqb2766)
It doesn't say that it's isosceles. Consider the large triangle, can you get ACB using the sin rule?
Then x is given by the angles in a triangle adding to 180.
hi how should i figure out ACB
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mqb2766
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(Original post by Madz178)
hi how should i figure out ACB
Use the sin rule in the large triangle.
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thanks for the help

(Original post by mqb2766)
Use the sin rule in the large triangle
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