# Edexcel A Level Further Maths Core Pure 1 Complex numbers help

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so i have the following question

(3√2+i) -(√2-i)

i am fine with the surd part of the question the problem is with the (i) and (-i) how do you deal with that for example if it was

(3√2+6i) -(√2-3i)

you would lay it out

(3√2-√2)- (6-3)i

which would obviously give you in the form a+bi where a,b are ∈ of ℝ

uou would get (3√2-√2)= 2√2 and (6-3)i you would multiply to get 3i

but when you have a question like (3√2+i) -(√2-i) when showing working would you just write out the imaginary part to the question as (+1-1)i or would you write it a different way i know how to do it just when it is a singular positive i or negative i in the question i don't know how to approach that

(3√2+i) -(√2-i)

i am fine with the surd part of the question the problem is with the (i) and (-i) how do you deal with that for example if it was

(3√2+6i) -(√2-3i)

you would lay it out

(3√2-√2)- (6-3)i

which would obviously give you in the form a+bi where a,b are ∈ of ℝ

uou would get (3√2-√2)= 2√2 and (6-3)i you would multiply to get 3i

but when you have a question like (3√2+i) -(√2-i) when showing working would you just write out the imaginary part to the question as (+1-1)i or would you write it a different way i know how to do it just when it is a singular positive i or negative i in the question i don't know how to approach that

Last edited by liamlarner; 4 weeks ago

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#2

(Original post by

so i have the following question

(3√2+i) -(√2-i)

i am fine with the surd part of the question the problem is with the (i) and (-i) how do you deal with that for example if it was

(3√2+6i) -(√2-3i)

you would lay it out

(3√2-√2)- (6-3)i

which would obviously give you in the form a+bi where a,b are ∈ of ℝ

uou would get (3√2-√2)= 2√2 and (6-3)i you would multiply to get 3i

but when you have a question like (3√2+i) -(√2-i) when showing working would you just write out the imaginary part to the question as (+1-1)i or would you write it a different way i know how to do it just when it is a singular positive i or negative i in the question i don't know how to approach that

**liamlarner**)so i have the following question

(3√2+i) -(√2-i)

i am fine with the surd part of the question the problem is with the (i) and (-i) how do you deal with that for example if it was

(3√2+6i) -(√2-3i)

you would lay it out

(3√2-√2)- (6-3)i

which would obviously give you in the form a+bi where a,b are ∈ of ℝ

uou would get (3√2-√2)= 2√2 and (6-3)i you would multiply to get 3i

but when you have a question like (3√2+i) -(√2-i) when showing working would you just write out the imaginary part to the question as (+1-1)i or would you write it a different way i know how to do it just when it is a singular positive i or negative i in the question i don't know how to approach that

for first question the imaginary part is [1-(-1)]i so 2i

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(Original post by

(3√2-√2)- (6-3)i should be (3√2-√2) - [6-(-3)]i so 2√2 + 9i ??

for first question the imaginary part is [1-(-1)]i so 2i

**golgiapparatus31**)(3√2-√2)- (6-3)i should be (3√2-√2) - [6-(-3)]i so 2√2 + 9i ??

for first question the imaginary part is [1-(-1)]i so 2i

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Yeah what i thought representing them as 1 and minus 1 because it is i

**liamlarner**)Yeah what i thought representing them as 1 and minus 1 because it is i

If you have

z = a + bi

and

w = c + di

then

z + w = (a + bi) + (c + di) = (a+c) + (b+d)i

z - w = (a + bi) - (c + di) = (a-c) + (b-d)i

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(Original post by

Sorry, not really sure what do you mean

If you have

z = a + bi

and

w = c + di

then

z + w = (a + bi) + (c + di) = (a+c) + (b+d)i

z - w = (a + bi) - (c + di) = (a-c) + (b-d)i

**golgiapparatus31**)Sorry, not really sure what do you mean

If you have

z = a + bi

and

w = c + di

then

z + w = (a + bi) + (c + di) = (a+c) + (b+d)i

z - w = (a + bi) - (c + di) = (a-c) + (b-d)i

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