neney
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the line L has equation y=2x + 8
the line L crosses the x-axis at the point A
the line M is perpendicular to line L and passes through the point A

a) find the coordinates of point A
b) find the equation of line M

so i understand that line M would have y = -1/2x + c but have no idea how to find point A
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mqb2766
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(Original post by neney)
the line L has equation y=2x + 8
the line L crosses the x-axis at the point A
the line M is perpendicular to line L and passes through the point A

a) find the coordinates of point A
b) find the equation of line M

so i understand that line M would have y = -1/2x + c but have no idea how to find point A
Y=0 when it crosses the x axis.
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alisha.h
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(Original post by neney)
the line L has equation y=2x + 8
the line L crosses the x-axis at the point A
the line M is perpendicular to line L and passes through the point A

a) find the coordinates of point A
b) find the equation of line M

so i understand that line M would have y = -1/2x + c but have no idea how to find point A
if A crosses the x-axis then it’s y co-ordinate would be 0, so the find A’s x co-ordinate you sub 0 into y —> 0=2x +8, x=-4, so A is the point (-4,0)
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